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EastWind [94]
2 years ago
9

The standard kilogram is in the shape of a circular cylinder with its height equal to its diameter. Show that, for a circular cy

linder of fixed volume, this equality gives the smallest surface area, thus minimizing the effects of surface contamination and wear.
Mathematics
1 answer:
oksano4ka [1.4K]2 years ago
5 0
Well, it can be easily done by differentiating function of area with respect to one of either height or radii/diameter (if calculus is enabled).say:A=pi*r^2 + 2pi*r*hV=pi*r^2*h or h=V/(pi*r^2)thenA=pi*r^2 + 2pi*r*V/(pi*r^2)to minimize surface area, we make dA/dr = 0try to do the rest, you'll find 2r = h
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A government official is in charge of allocating social programs throughout the city of Vancouver. He will decide where these so
otez555 [7]

Answer: (0.132132, 0.274368)

Step-by-step explanation:

Given : A simple random sample of 123 people living in Gastown and finds that 25 have an annual income that is below the poverty line.

i.e. n= 123

\hat{p}=\dfrac{25}{123}\approx0.203252

Critical value for 95% confidence interval : z_{\alpha/2}=1.96

Confidence interval for population :

\hat{p}\pm z_{\alpha/2}\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}

i.e. 0.203252\pm (1.96)\sqrt{\dfrac{0.203252(1-0.203252)}{123}}

0.203252\pm (1.96)\sqrt{\dfrac{0.203252(1-0.203252)}{123}}\\\\\0.203252\pm0.071118\\\\=(0.20325-0.071118,\ 0.203252+0.071118)\\\\=(0.132132,\ 0.274368)

Hence, the 95% confidence interval for the true proportion of Gastown residents living below the poverty line : (0.132132, 0.274368)

5 0
2 years ago
Fill in the blanks. a. A​ relative-frequency distribution is to a variable as a​ __________ distribution is to a random variable
RideAnS [48]

Answer:

a. A​ relative-frequency distribution is to a variable as a​ ___probability_______ distribution is to a random variable. b. A​ relative-frequency histogram is to a variable as a​ _____probability_____ histogram is to a random variable.

Step-by-step explanation:

Probability is a type of mathematics which deals with numerical descriptions of how likely an event would occur, or how likely it is that a the occurrence would be true. The probability of an event is usually between 0 and 1,

where 0 represent impossibility and 1 represents the chance of it occurring.

4 0
2 years ago
HELP PLEASE I NEEED HELP!!!!
Nina [5.8K]
It is d just trust me
4 0
2 years ago
*NO 194 39% 13:08 Pilih jawaban yang paling tepat Segitiga PQR dan segitiga XYZ 5 poin merupakan dua segitiga yang kongruen. Bes
Illusion [34]

Answer:

Option d. PQ = YZ

Step-by-step explanation:

<u><em>The question in English is</em></u>

Choose the most appropriate answer. The PQR triangle and the XYZ triangle are two congruent triangles. The angle P = the angle Y and PR = YX. Side pairs of the same length are ... a. PQ = XZ b. QR = YZ c. QR = XY d. PQ = YZ

we know that

If two triangles are congruent, then its corresponding sides and its corresponding angles are congruent

Corresponding sides are named using pairs of letters in the same position on either side of the congruence statement

so

we have that

m\angle P=m\angle Y

PR=YX

so

Triangle PQR is congruent with Triangle YZX

That means

<em><u>Corresponding angles</u></em>

m\angle P=m\angle Y

m\angle Q=m\angle Z

m\angle R=m\angle X

<u><em>Corresponding sides</em></u>

PQ=YZ\\QR=ZX\\PR=YX

8 0
2 years ago
A circle with radius of \greenD{5\,\text{cm}}5cmstart color #1fab54, 5, start text, c, m, end text, end color #1fab54 sits insid
Marat540 [252]

Answer:

The area of the shaded region is 42.50 cm².

Step-by-step explanation:

Consider the figure below.

The radius of the circle is, <em>r</em> = 5 cm.

The sides of the rectangle are:

<em>l</em> = 11 cm

<em>b</em> = 11 cm.

Compute the area of the shaded region as follows:

Area of the shaded region = Area of rectangle - Area of circle

                                            =[l\times b]-[\pi r^{2}]\\\\=[11\times 11]-[3.14\times 5\times 5]\\\\=121-78.50\\\\=42.50

Thus, the area of the shaded region is 42.50 cm².

7 0
2 years ago
Read 2 more answers
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