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kvv77 [185]
2 years ago
4

At lunch, Kira eats either a burrito containing 490 milligrams of sodium or a peanut butter sandwich containing 700 milligrams o

f sodium. Her doctor told her to reduce her sodium to no more than 4,000 milligrams per week. Which inequality represents x, the number of microwave burritos, and y, the number of peanut butter sandwiches, she can eat each week?
490x + 700y < 4000
490x + 700y ≤ 4000
490x + 700y  > 4000
490x + 700y ≥ 4000
Mathematics
2 answers:
sukhopar [10]2 years ago
6 0
The correct answer is <span>490x + 700y ≤ 4000

hope this helps you</span>
EleoNora [17]2 years ago
3 0
The second one.

Hope this helps :)
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What is the solution set of the equation below? 3|5 − x| + 2 = 29
Yuki888 [10]

Answer:

x = -4, 14

Step-by-step explanation:

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Resale Value Garland Mills purchased a certain piece of machinery 2 years ago for $500,000. Its present resale value is $420,000
Natasha2012 [34]

Answer:

260,000

Step-by-step explanation:

The value decreases by 40,000 per year (500000-42000/2 years) the value will decrease by 240000 in six (4 years plus 2 years already passed) years. 6 x 40,000 =240000

So, the value should be 260,000 (500000-240000)

Or

year 1 500000-40000=460000

year 2 460000-40000=420000

year 3 420000-40000=380000

year 4 380000-40000=340000

year 5 340000-40000=300000

year 6 300000-40000=260000

6 0
2 years ago
The production department has installed a new spray machine to paint automobile doors. As is common with most spray guns, unsigh
marta [7]

Answer:

10000*0.6065=6065

A. about 6,065

Step-by-step explanation:

Definitions and concepts

The Poisson process is useful when we want to analyze the probability of ocurrence of an event in a time specified. The probability distribution for a random variable X following the Poisson distribution is given by:

P(X=x) =\lambda^x \frac{e^{-\lambda}}{x!}

And the parameter \lambda represent the average ocurrence rate per unit of time.

For this distribution the expected value is the same parameter \lambda  

E(X)=\mu =\lambda=0.5  , Var(X)=\lambda=0.5, Sd(X)=707

Solution to the problem

We want "how many would have no blemishes" so first we need to find the probability that X=0, since X represent on this case the number of blemishes on each door. And if we use the mass function we got this:

P(X=0) =0.5^0 \frac{e^{-0.5}}{0!}=0.6065

And now since we have a total of 10000 doors painted we can find how many we would expect with no blemishes:

10000*0.6065=6065

A. about 6,065

4 0
2 years ago
The letters G, E, N, I, D, S are placed in a bag. What is the probability that the letters are randomly pulled from the bag in t
Gelneren [198K]

Answer as a fraction = 1/5040

Answer in decimal form (approximate) = 0.000198

Answer in percentage form (approximate) = 0.0198%

=========================================================

Explanation:

There is only one ordering of the letters to get DESIGN out of 5040 different permutations. The 5040 comes from the fact that 7*6*5*4*3*2*1 = 5040. In shorthand notation, use factorials to say 7! = 5040. Notice how we started with 7 and counted down until reaching 1, multiplying all along the way. You could use the nPr permutation formula to get the same result of 5040 (use n = 7 and r = 7).

So because we have 1 way to order the letters (getting DESIGN) out of 5040 ways total, this means the probability is the fraction 1/5040. Use your calculator to find that 1/5040 = 0.000198 approximately. Move the decimal over 2 spots to the right to convert 0.000198 to 0.0198%

4 0
2 years ago
We are told that the data is representative of the two populations (U.S. males aged 20-29 years and U.S. males aged 75+ years),
tiny-mole [99]

Answer:

The data provide strong evidence that young men weigh more on average than old men in the U.S

Step-by-step explanation:

Given :

The null hypothesis ; H0 : μ1 = μ2

The alternative hypothesis ; H1 : μ1 > μ2

T score = 5.3 ; Pvalue = < 0.0001

The decision region :

If Pvalue < α ; We reject the Null

If Pvalue > α ; We fail to reject the Null

When the α - level isn't stated, we usually assume a α - level of 5%

However, even at lower alpha level of 1% = 0.01 ;

The Pvalue < α

Hence, we can conclude that there is significant evidence that there is difference in the mean weight of young men and old men in the U.S

3 0
2 years ago
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