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Mashutka [201]
2 years ago
3

Calorimetry can also be used to determine nutritional Calories, which are actually kilocalories. One (1) nutritional Calorie = 1

000 calories, and 1 calorie = 4.184 J. When 1.0 g of a snack cake is combusted in a constant-volume bomb calorimeter with a heat capacity (including its water) of 10.0 kJ/°C, the temperature of the calorimeter rises by 1.42°C. How many nutritional calories (Calories) are in one serving (28 g) of this snack cake? Enter your answer to three significant figures in units of Calories.
Health
1 answer:
bixtya [17]2 years ago
7 0

Answer:

95.0 nutritional calories  

Explanation:

Given that:

One (1) nutritional Calorie = 1000 calories,  

1 calorie = 4.184 J

Energy released when 1.0 g of a snack cake is combusted = Heat capacity(q) × temperature rise of the calorimeter ( ΔT)

= 10.0 kJ/°C × 1.42 °C

= 14.2 kJ

Energy released when 28 g  snack cakes are used = 14.2 kJ × 28

= 397.6 kJ

In calories, the energy released =  \frac{397.6*10^3J}{4.184J}       (since; 1 calorie = 4.184 J)

= 95028.68069

≅ 95.029 × 10³ calories

∴ the nutritional calories in one serving (28 g) of this snack cake can be calculated as:

= \frac{95.029*10^3calories}{1000 calories}

= 95.029 nutritional calories

= 95.0 nutritional calories  (to 3 significant figures)

∴ there are 95.0 nutritional calories in one serving (28 g) of this snack cake.

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