Uniform internal heat generation at q˙ = 2.75 × 107 W/m3 is occurring in a cylindrical nuclear reactor fuel rod of 40-mm diame
ter, and under steady-state conditions the temperature distribution is of the form T(r)=a+br2, where T is in degrees Celsius and r is in meters, while a= 800 °C and b= -4.167 × 105 °C/m2. The fuel rod properties are k= 30 W/m·K, rho= 1100 kg/m3, and cp= 800 J/kg·K.Find the steady state temperature gradient, dT/dr, at the outer surface of the rod, in °C/m.What is the steady state rate of heat transfer at the outer surface, in W/m?Immediately after the sudden increase in reactor power level (at t= 0 sec), what is the temperature at the centerline?Immediately after the sudden increase in reactor power level (at t= 0 sec), what is the time rate of temperature change, dT/dt, at the centerline, in °C/s?
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Answer:
Yes, the flow is turbulent.
Explanation:
Reynolds number gives the nature of flow. If he Reynolds number is less than 2000 then the flow is laminar else turbulent.
Given:
Diameter of pipe is 10mm.
Velocity of the pipe is 1m/s.
Temperature of water is 200°C.
The kinematic viscosity at temperature 200°C is m2/s.
Calculation:
Step1
Expression for Reynolds number is given as follows:
Here, v is velocity, is kinematic viscosity, d is diameter and Re is Reynolds number.
Substitute the values in the above equation as follows:
Re=64226.07579
Thus, the Reynolds number is 64226.07579. This is greater than 2000.
Hence, the given flow is turbulent flow.