There r many ways to represent slope:
Rise / run
x2-x1 over y2-y1
Ratio of the change in y (rise) over the change in x (run)
Let's simplify step-by-step.
<span><span>0.2<span>(<span><span>3b</span>−<span>15c</span></span>)</span></span>+<span>6c
</span></span>Distribute:<span>=<span><span><span><span>(0.2)</span><span>(<span>3b</span>)</span></span>+<span><span>(0.2)</span><span>(<span>−<span>15c</span></span>)</span></span></span>+<span>6c
</span></span></span><span>=<span><span><span><span>0.6b</span>+</span>−<span>3c</span></span>+<span>6c
</span></span></span>Combine Like Terms:
<span>=<span><span><span>0.6b</span>+<span>−<span>3c</span></span></span>+<span>6c
</span></span></span><span>=<span><span>(<span>0.6b</span>)</span>+<span>(<span><span>−<span>3c</span></span>+<span>6c</span></span>)
</span></span></span><span>=<span><span>0.6b</span>+<span>3<span>c</span></span></span></span>
Answer:
(ai) The correct answer is the first option; The amount of tax the student is willing to add to a gallon of gasoline.
(aii) The correct answer is the last option; Whether the student believes that global warming is a serious issue or not.
(b) The correct answer is the first option; two-sample t interval
Step-by-step explanation:
A response variable in statistics is the idea or concept of needs to be proven right or wrong. It remains a response variable until it has been proven.
An explanatory variable simply means an independent variable. It doesn't depend on any other variable and at the same time, it can be manipulated.
In construct a 95% confidence interval to compare the two groups, two-sample t test is the appropriate t test to use.
Answer:
<h3>
- 128 Superscript StartFraction 3 Over x EndFraction
</h3><h3>
- (4RootIndex 3 StartRoot 2 EndRoot)x
</h3><h3>
- (4 (2 Superscript one-third Baseline) ) Superscript x</h3><h3>
Step-by-step explanation:</h3>
Given the indicinal equation ![(\sqrt[3]{128} )^{x}\\](https://tex.z-dn.net/?f=%28%5Csqrt%5B3%5D%7B128%7D%20%29%5E%7Bx%7D%5C%5C)
According to one of the law of indices,
![(\sqrt[a]{m} )^{b}\\= (\sqrt{m})^\frac{b}{a}](https://tex.z-dn.net/?f=%28%5Csqrt%5Ba%5D%7Bm%7D%20%29%5E%7Bb%7D%5C%5C%3D%20%28%5Csqrt%7Bm%7D%29%5E%5Cfrac%7Bb%7D%7Ba%7D)
Applying this law to the question;
![(\sqrt[3]{128} )^{x}\\ = {128} ^\frac{x}{3}\\ \\= (\sqrt[3]{64*2})^{x} \\ = (4\sqrt[3]{2})^{x} \\= (4(2^{1/3} )^{x} )](https://tex.z-dn.net/?f=%28%5Csqrt%5B3%5D%7B128%7D%20%29%5E%7Bx%7D%5C%5C%20%3D%20%7B128%7D%20%5E%5Cfrac%7Bx%7D%7B3%7D%5C%5C%20%5C%5C%3D%20%28%5Csqrt%5B3%5D%7B64%2A2%7D%29%5E%7Bx%7D%20%5C%5C%20%3D%20%284%5Csqrt%5B3%5D%7B2%7D%29%5E%7Bx%7D%20%5C%5C%3D%20%284%282%5E%7B1%2F3%7D%20%29%5E%7Bx%7D%20%29)
The following are therefore true based on the following calculation
128 Superscript StartFraction 3 Over x EndFraction
(4RootIndex 3 StartRoot 2 EndRoot)x
(4 (2 Superscript one-third Baseline) ) Superscript x
