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hodyreva [135]
2 years ago
7

The UML models operations by listing the operation name preceded by an access modifier. A(n) ________ indicates a public operati

on in the UML. - + p *
Computers and Technology
2 answers:
Nastasia [14]2 years ago
5 0

Answer / Explanation

The question seem not to be complete. It can be found in search engines.

Kindly find the complete question below.

Question

The UML models operations by listing the operation name followed by a set of ____. A plus sign (+) in front of the operation name indicates that the operation is a public one in the UML (i.e., a public method in Java).

Answer:

To properly answer this question, let us first define what a UML is:

UML can be defined as or is simply refereed to as Unified Modelling Language. It is considered as the standard for modeling language that enables designers and developers to specify, visualize, construct and document object or programs made by them in the areas of software systems, Thus, UML makes this objects developed by computer gurus secure and robust in execution.

If we now go back to the question asked while referencing the explanation given of what a UML is, the answer to the question is

parentheses.

However, if the original question being asked is valid, the answer to it would be : sign (+) in front of the operation name

Nataly [62]2 years ago
3 0

Answer:

parentheses

Explanation:

The Unified Modeling Language (UML) is a kind of fixed structure that explains the structure of a system by showing the system's classes, interface, attributes, data types, operations and the relationships among objects. UML models operates by listing the operation name preceded by an access modifier, A Parenthesis indicates a public operation.

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Recall the problem of finding the number of inversions. As in the text, we are given a sequence of n numbers a1, . . . , an, whi
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Answer:

The algorithm is very similar to the algorithm of counting inversions. The only change is that here we separate the counting of significant inversions from the merge-sort process.

Algorithm:

Let A = (a1, a2, . . . , an).

Function CountSigInv(A[1...n])

if n = 1 return 0; //base case

Let L := A[1...floor(n/2)]; // Get the first half of A

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//Recurse on L. Return B, the sorted L,

//and x, the number of significant inversions in $L$

Let B, x := CountSigInv(L);

Let C, y := CountSigInv(R); //Do the counting of significant split inversions

Let i := 1;

Let j := 1;

Let z := 0;

// to count the number of significant split inversions while(i <= length(B) and j <= length(C)) if(B[i] > 2*C[j]) z += length(B)-i+1; j += 1; else i += 1;

//the normal merge-sort process i := 1; j := 1;

//the sorted A to be output Let D[1...n] be an array of length n, and every entry is initialized with 0; for k = 1 to n if B[i] < C[j] D[k] = B[i]; i += 1; else D[k] = C[j]; j += 1; return D, (x + y + z);

Runtime Analysis: At each level, both the counting of significant split inversions and the normal merge-sort process take O(n) time, because we take a linear scan in both cases. Also, at each level, we break the problem into two subproblems and the size of each subproblem is n/2. Hence, the recurrence relation is T(n) = 2T(n/2) + O(n). So in total, the time complexity is O(n log n).

Explanation:

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Answer:

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Explanation:

This question is incomplete, we need a diagram and four options to resolve this questions, I attached the diagram and the options.

- The process will work all stages in the "Access Customer Account" page until the error is thrown and then focus would move to the breakpoint at "Get Customer Details" stage.

- The process will work all stages in the "Access Customer Account" page until the error is thrown and then focus would move to the "Recover1" stage.

- The process will work all stages in the "Access Customer Account" page until the error is thrown and then focus would move to the stage containing the error on the "Access Customer Account" page.

- The process will work all stages in the "Access Customer Account" page until the error is thrown and then focus would move to the "Exception1" stage.

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But in this particular example, we must use the STEP OUT BUTTON, What means this?

The process it's going be executed, but won't show any error or message, because we have used the STEP OUT BUTTON.

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