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hodyreva [135]
2 years ago
7

The UML models operations by listing the operation name preceded by an access modifier. A(n) ________ indicates a public operati

on in the UML. - + p *
Computers and Technology
2 answers:
Nastasia [14]2 years ago
5 0

Answer / Explanation

The question seem not to be complete. It can be found in search engines.

Kindly find the complete question below.

Question

The UML models operations by listing the operation name followed by a set of ____. A plus sign (+) in front of the operation name indicates that the operation is a public one in the UML (i.e., a public method in Java).

Answer:

To properly answer this question, let us first define what a UML is:

UML can be defined as or is simply refereed to as Unified Modelling Language. It is considered as the standard for modeling language that enables designers and developers to specify, visualize, construct and document object or programs made by them in the areas of software systems, Thus, UML makes this objects developed by computer gurus secure and robust in execution.

If we now go back to the question asked while referencing the explanation given of what a UML is, the answer to the question is

parentheses.

However, if the original question being asked is valid, the answer to it would be : sign (+) in front of the operation name

Nataly [62]2 years ago
3 0

Answer:

parentheses

Explanation:

The Unified Modeling Language (UML) is a kind of fixed structure that explains the structure of a system by showing the system's classes, interface, attributes, data types, operations and the relationships among objects. UML models operates by listing the operation name preceded by an access modifier, A Parenthesis indicates a public operation.

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2 years ago
The compare_strings function is supposed to compare just the alphanumeric content of two strings, ignoring upper vs lower case a
Korolek [52]

Answer:

There is a problem in the given code in the following statement:

Problem:

punctuation = r"[.?!,;:-']"

This produces the following error:

Error:

bad character range

Fix:

The hyphen - should be placed at the start or end of punctuation characters. Here the role of hyphen is to determine the range of characters. Another way is to escape the hyphen - using using backslash \ symbol.

So the above statement becomes:

punctuation = r"[-.?!,;:']"  

You can also do this:

punctuation = r"[.?!,;:'-]"  

You can also change this statement as:

punctuation = r"[.?!,;:\-']"

Explanation:

The complete program is as follows. I have added a print statement print('string1:',string1,'\nstring2:',string2) that prints the string1 and string2 followed by return string1 == string2  which either returns true or false. However you can omit this print('string1:',string1,'\nstring2:',string2) statement and the output will just display either true or false

import re  #to use regular expressions

def compare_strings(string1, string2):  #function compare_strings that takes two strings as argument and compares them

   string1 = string1.lower().strip()  # converts the string1 characters to lowercase using lower() method and removes trailing blanks

   string2 = string2.lower().strip()  # converts the string1 characters to lowercase using lower() method and removes trailing blanks

   punctuation = r"[-.?!,;:']"  #regular expression for punctuation characters

   string1 = re.sub(punctuation, r"", string1)  # specifies RE pattern i.e. punctuation in the 1st argument, new string r in 2nd argument, and a string to be handle i.e. string1 in the 3rd argument

   string2 = re.sub(punctuation, r"", string2)  # same as above statement but works on string2 as 3rd argument

   print('string1:',string1,'\nstring2:',string2)  #prints both the strings separated with a new line

   return string1 == string2  # compares strings and returns true if they matched else false

#function calls to test the working of the above function compare_strings

print(compare_strings("Have a Great Day!","Have a great day?")) # True

print(compare_strings("It's raining again.","its raining, again")) # True

print(compare_strings("Learn to count: 1, 2, 3.","Learn to count: one, two, three.")) # False

print(compare_strings("They found some body.","They found somebody.")) # False

The screenshot of the program along with its output is attached.

4 0
2 years ago
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