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STatiana [176]
2 years ago
5

To estimate the average annual expenses of students on books and class materials a sample of size 36 is taken. The sample mean i

s $850 and the sample standard deviation is $54. A 99% confidence interval for the population mean is:_______.A) $823.72 to $876.28.
B) $832.36 to $867.64.
C) $826.82 to $873.18.
D) $825.48 to $874.52.
Mathematics
1 answer:
Elena L [17]2 years ago
6 0

Answer:

C) $826.82 to $873.18.

Step-by-step explanation:

Sample mean (M) = $850

Standard deviation (s) = $54

sample size (n) = 36

Z for 99% confidence interval (Z) = 2.576

The confidence interval is determined by the following relationship:

M \pm Z*\frac{s}{\sqrt{n}}

Applying the given values, the lower (L) and upper (U) values are:

850 \pm 2.576*\frac{54}{\sqrt{36}}\\L=\$826.82\\U=\$873.18

The answer is C) $826.82 to $873.18.

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The data is:

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We want to find the oldest, so we need to find the larger number of the 4 we have.

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2 years ago
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A. 44.82%

B.

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C.

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Step-by-step explanation:

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