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Lorico [155]
2 years ago
4

En un barco, 1/7 del número de tripulantes se encarga del mantenimiento de la maquinaria, 2/7 de la cocina, 3/7 de las recámaras

y pasillos, y los 18 restantes son oficiales
Mathematics
1 answer:
yaroslaw [1]2 years ago
8 0

Answer:

see the explanation

Step-by-step explanation:

<u><em>The question in English is</em></u>

On a ship, 1/7 of the crew members maintain the machinery, 2/7 the kitchen, 3/7 the bedrooms and corridors, and the remaining 18 are officers

Let

x ----> members that maintain the machinery

y ---->members that maintain the kitchen

z ----> members that maintain bedrooms and corridors

w ----> members that are officers

T ----> total number of members

we know that

The total sum of the fractions must be equal to 1

\frac{1}{7}+\frac{2}{7}+\frac{3}{7}+w=1

w=1-\frac{6}{7}

w=\frac{1}{7}

Remember that

The number of officers is 18

so

18=\frac{1}{7}T

Find out the total number of members

solve for T

T=18(7)=126\ members

Find out the number of members that maintain the machinery

x=\frac{1}{7}T

x=\frac{1}{7}(126)=18\ members

Find out the number of members that maintain the kitchen

y=\frac{2}{7}T

y=\frac{2}{7}(126)=36\ members

Find out the number of members that maintain bedrooms and corridors

z=\frac{3}{7}T

z=\frac{3}{7}(126)=54\ members

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In Quebec, 90 percent of the population subscribes to the Roman Catholic religion. In a random sample of eight Quebecois, find t
AysviL [449]

Answer:

Probability that the sample contains at least five Roman Catholics = 0.995 .

Step-by-step explanation:

We are given that In Quebec, 90 percent of the population subscribes to the Roman Catholic religion.

The Binomial distribution probability is given by;

 P(X = r) = \binom{n}{r}p^{r}(1-p)^{n-r} for x = 0,1,2,3,.......

Here, n = number of trials which is 8 in our case

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So, P(X >= 5) = P(X = 5) + P(X = 6) + P(X = 7) + P(X = 8)

= \binom{8}{5}0.9^{5}(1-0.9)^{8-5} + \binom{8}{6}0.9^{6}(1-0.9)^{8-6} + \binom{8}{7}0.9^{7}(1-0.9)^{8-7} + \binom{8}{8}0.9^{8}(1-0.9)^{8-8}

= 56 * 0.9^{5} * (0.1)^{3} + 28 * 0.9^{6} * (0.1)^{2} + 8 * 0.9^{7} * (0.1)^{1} + 1 * 0.9^{8}

= 0.995

Therefore, probability that the sample contains at least five Roman Catholics is 0.995.

3 0
2 years ago
Solve the compound inequality. Graph the solution set.<br> -2x&lt;2x-4&lt;4
Arte-miy333 [17]
I hope this helps you

-2x <2x-4

4 <4x

1 <x

2x-4 <4

2x <8

x <4

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The porter family is moving from Baltimore, Maryland, to San Francisco, California. They would like to know what the difference
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Answer:

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Step-by-step explanation:

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