Algebra 1 ) U. Checkpoint: Systems of equations and inequalities LOW

Mathematics

1 answer:

krek1111 [17]2 years ago

7 0

Answer:algebra ok

Step-by-step explanation:

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The given values are discrete. Use the continuity correction and describe the region of the normal distribution that corresponds

Bumek [7]

Answer:

Option B) The area to the right of 35.5

Step-by-step explanation:

Data:

Let the probability of the correct answers be denoted by the letter C.

The probability of no more than 35 defective CD's can be 35 or less. Therefore, it is presented as follows:

P ≤ 35

Let, the probability of more than 44 correct answers can be presented like this:

P > 44

Therefore, combining the two inequalities gives an area at the right of 35.5

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2 years ago

IM OFFERING 100 POINTS, I NEED HELP AND ITS TIMED

Assoli18 [71]

Answer:

look below

Step-by-step explanation:

Part A: The y-intercept is $1,500

The x-intercept is 20 days

Part B: Equation of the line in point-slope form is y - 1350 = -75×(x - 2) Equation of the line in slope-intercept form is y = -75·x + 1500

Equation of the line in standard form is y + 75·x = 1500

Part C:

f(x) = -75·x + 1500

Part D: $1,125 Step-by-step explanation: The information given are; x, g(x) 0, $1,500 2, $1,350 4, $1,200 The equation of a straight line relation between the x, and y, coordinates in slope and intercept form is y = m·x + c Where; m = The slope c = The y-intercept From the data, we have two points, (x₁, y₁), (x₂, y₂) given as (0, 1,500), (2, 1350); The y-intercept = y at x = 0 = 1,500 y = -75·x + 1500 x = 1500/75 = 20

Read more at Answer.Ya.Guru – https://answer.ya.guru/questions/5966450-the-table-of-values-represents-a-linear-function-g-x-where-x-is.html

I hope this helps I know its kinda confusing

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2 years ago

Repair calls are handled by one repairman at a photocopy shop. Repair time, including travel time, is exponentially distributed,

seropon [69]

Answer and Step-by-step explanation:

Data provided in the question

Mean = 1.1 hours per call =

R = Mean rate = 1.6 per eight hour day

$\mu$ = $\frac{8}{1.6}$ = 5 per day