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Marysya12 [62]
1 year ago
11

The center of gravity method determines the best x and y coordinates for multiple faclities by finding a central location and th

en assigning the facilities around the periphery of that location. True or false?
Business
1 answer:
babymother [125]1 year ago
8 0

Answer:

The answer is True.

Explanation:

The center of gravity method is a concept under <em>Operations Management</em> as it relates to facilities distribution such as warehouses or fulfillment centers.

Center of Gravity Strategy/Method is defined as a concept that seeks to calculate geographic coordinates for a potential single new facility that will minimize costs. Under this approach the main factors considered are:

  • Cost of Shipping
  • Markets
  • Volume of goods shipped

Operations managers prefer to use this approach in siting the location of their facilities because:

  • It minimizes cost.
  • It is simple to compute
  • It takes in to consideration existing facilities

How to use the Center of Gravity Method

Step 1:

  • Place existing facility(ies) such warehouse, fulfillment center, and distribution center locations in a coordinate grid.
  • situate the grid on an ordinary map.
  • The distances between the facilities must be noted.

Step 2:

Then, using the equations below,

   Fx= ∑ dix Vi/ ∑ Vi

   Fy= ∑ diy Vi/ ∑ Vi

Proceed to calculate the X and Y coordinates using these equations where Fx is the X (horizontal axis) coordinate for the new facility, and

Fy is the Y (vertical axis) coordinate for the new facility, dix is the X coordinate of the current location, diy is the Y coordinate of the existing location, and Vi is the volume of goods moved to or from the <em>i</em>th location.

Step 3:

After you have obtained the X and Y coordinates place that location on the map.

This approach allows for point of departure – or, literally, a starting point of where (from the perspective of longitude and latitude) you options are for where to grow your fulfillment or logistics network.

Cheers!

 

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Alt Corp. issues 5,000 shares of $10 par value common stock at $14 per share. When the transaction
TiliK225 [7]

Answer:

c. Common Stock $50,000 and Paid-in Capital in Excess of Par Value $20,000.

Explanation:

The journal entry is shown below:

Cash $70,000  (5,000 shares × $14)

     To Common stock $50,000  (5,000 shares × $10)

      To Additional Paid in capital in excess of par value - Common stock   $20,000  (5,000 shares × $4)

(Being the issuance of the common stock is recorded)

For recording this we debited the cash as it increased assets and at the same time it also increased the overall stockholder equity so common stock and the additional paid in capital for common stock is credited

6 0
1 year ago
After nearly 20 years with his company, Mike's job was outsourced. He wants his new job to offer not only a good wage but also j
Sedbober [7]

Answer:

a. intrinsic rewards

Explanation:

Intrinsic rewards at the workplace are those that meet personal, internal needs. These intrisic rewards can be summed up in job satisfaction and sense of accomplishment, but what makes a job satisfying, and what makes a worker feel accomplished is subjective, and varies from person to person.

Mike is focusing on the intrinsic rewards of his new job because he is giving more importance to this subjective aspects explained above than to external factors such as status, or wage.

8 0
2 years ago
Suppose every Buick owner's demand for gasoline is 20 - 5 p for p less than or equal to 4 and 0 for p &gt; 4. Every Dodge owner'
mario62 [17]
I think the answer is b
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2 years ago
Uniform Supply accepted a $4,800, 90-day, 10% note from Tracy Janitorial on October 17. If the note is dishonored, but Uniform S
Vesna [10]

Answer:

Check the explanation

Explanation:

Solution: Journal entry for the purpose would be:

Cash A/c. Dr. 4920

Interest Revenue 20

Interest Receivable 100

Note Receivable. 4800

(Being due amount on note along with the interest collected)

Note:

Total interest on Note= 4800 x 10% x90/ 360 days

= $120

Interest accrued in previous year=$ 120 x 2.5/3 =$ 100

(i.e. represent in entry by way of interest receivable)

Interest income for current period =$(120-100)=$20

Assumed: Financial year ended on December 31st.

8 0
2 years ago
Part X requires machining on a milling machine (operations A and B are required).
Inga [223]

Answer:atleast 5 machines

Explanation:

Quantity required (Q) = 3000

Maintainace due = 500 parts

3000 / 500 = 5 = 6 Maintainace

Repair time = 6 × 30 minutes = 300 minutes = 5 hours.

operation time = 5 × 18 × 60 = 5400 minutes

Total operation time = Total operation hours - repair time

5400 - 300 = 5100 hours

For A:

(Standard time × Q) / (reliability × time efficiency × scrap × total working hours)

(3 × 3000) / (. 95×.95×5100)

9000/4602.75 = 1.96

For B:

(Standard time × Q) / (reliability × time efficiency × scrap × total working hours)

(5 × 3000) / (.95×.9×5100)

15000/4360.5 = 3.44

(1.96 + 3.44) = 166.56

=5. 4

5 0
2 years ago
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