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ZanzabumX [31]
2 years ago
8

A hacker stood outside a building and spun up a wireless network without anyone's knowledge. At that point, the hacker was able

to gain unauthorized access to a secure corporate network. Which of these is the name of this type of attack?
a. A DNS Cache Poisoning attackb. A Denial-of-Service (DoS) attackc. A Rogue AP (Access Point) attackd. SYN flood attack
Biology
1 answer:
gogolik [260]2 years ago
8 0
<h2>The correct option is (C)</h2>

Explanation:

  • A Rogue Access Point is any remote passageway that has been introduced on a system's wired foundation without the assent of the network's administrator or proprietor, in this manner giving unapproved remote access to the system's wired infrastructure.Most of the time, Rogue APs are set up by representatives who need remote access when none is accessible.
  • For example, marketing may need remote access for their travelling agents who continually bring PCs.Consumer-oriented access points  regularly don't have the executives interfaces and don't distinguish themselves on the system.
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The fact that choanoflagellates and collar cells of sponges resemble each other supports the inference that ________. Group of a
antoniya [11.8K]

Answer:

choanoflagellates and sponges are sister groups

Explanation:

The choanoflagellates are small unicellular organisms belonging to the Protista kingdom. These microorganisms are collared flagellates morphologically similar to the choanocyte cells of animal sponges, which have a central flagellum surrounded by a collar of microvilli. In consequence, it has been suggested that choanoflagellates may represent the closest living relatives of primitive metazoans (i.e., they are sister groups to sponges). This hypothesis has recently been supported by both molecular phylogenetic and comparative genomic analyses.

6 0
1 year ago
Which of the following statements is CORRECT regarding studies of character
pishuonlain [190]

Answer:

Explanation:

Assume that a student is given two different models of bacteria, with one model consisting of big bacteria and the other consisting of small bacteria. How can the student demonstrate the theory of endosymbiosis using the models?

5 0
2 years ago
Glucokinase has a Km value of 10.0 mM, whereas hexokinase has a Km value of 0.1 mM. This is consistent with which of the followi
Goshia [24]

Answer:

B. Glucokinase acts on glucose only at high glucose concentrations.

Explanation:

To understand the answer, first, we have to know that the Michaelis Menten kinetics requires to have a constant concentration of enzyme quantity to see what happens with the rate.

To determine that we can evaluate how much time takes the total consumption of substrate or the time taken to obtain a product.

We know that when an enzymatic reaction occurs, the enzyme accelerates the reaction by minimizing the activation energy.

Suppose we have the enzyme on this case glucokinase and hexokinase, and we going to make them react with the substrate, in this case, the glucose.

Any of both enzymes will be abbreviated as E, and glucose as a substrate will be abbreviated as S. And we have the following reaction:

E  +  S = ES = E + P

When ES is the enzyme-substrate complex, and P is the product of the reaction, in these case, when the hexokinase or glucokinase takes the glucose the product is the phosphorylation of the glucose.

We can see this reaction, for both enzymes or any enzyme as a graph (watch image attached).

This image explains that when you have a constant concentration of enzyme and you add more substrate, the velocity will rise but, when the reaction reaches the maxim velocity (Vmax), this value will be constant, and it is because all the enzyme active site are full with substrate already, so even if you add, the reaction will not accelerate.

Take a look at the graph and note the Km value related to the

1/2 Vmax. And the Km is finally just the substrate concentration when the half value of velocity is reached.

So, for any enzyme reaction, the Km value is the concentration of the substrate when the half higher value of velocity will be reached.

So for glucokinase, who has a Km value of 10 mM, and hexokinase with a Km = 0.1 mM we can say that glucokinase requires more quantity of substrate (glucose) to reach the maximum velocity, but hexokinase reaches the maximum velocity a very small quantity of glucose concentration. And that behavior has to be related to the higher affinity of glucose with the hexokinase instead of glucokinase.

For that reason the answer must be :

B. Glucokinase acts on glucose only at high glucose concentrations.

As you must know, glucokinase is an enzyme produced on the liver and has a higher specify for D-glucose instead for other hexoses, the glucokinase has a poor activity at lower blood concentration of glucose ( fast periods, before breakfast).

7 0
2 years ago
1)When a phosphate is transferred from ATP, it can phosphorylate another molecule. How could this assist in allowing a protein t
Andrews [41]

Answer/Explanation:

1) When phosphate is transferred from ATP, (which forms ADP and releases energy) it can phosphorylate another molecule. When this molecule is phosphorylated. It could become "energized" as it enters a higher energy state.

In this higher energy state, the protein has the energy to transfer molecules against a concentration gradient, which is an active process (requires energy).

2) Adenosine triphosphate contains three phosphate groups. The phosphate bonds are high energy. When ATP is hydrolyzed (water is added), these high energy phosphate bonds are broken and energy is released. This forms adenosine diphosphate (ADP).

3 0
2 years ago
During hemostasis, which process occurs first? A. Platelet aggregation B. Fibrinolysis C. Platelet adhesion D. Fibrinogen conver
OleMash [197]

Answer:

C. Platelet adhesion

Explanation:

Platelet adhesion comes first in the process of hemostasis.

The process of hemostasis has got three phases:

  • Vascular spasm
  • Platelet plug formation
  • Blood coagulation

The process occurs in the body in the event of a bleeding injury.

In the first phase, damaged blood vessels constrict to prevent more bleeding.

In the second phase, platelets adhere to damaged endothelium to form platelet plug.

In the third phase, fibrinogen is converted to fibrin to form a clot.

8 0
2 years ago
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