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Zigmanuir [339]
2 years ago
6

Program documentation _____. Group of answer choices describes the inputs, outputs, and processing logic for all program modules

consists of instructions and information for users who will interact with the system and includes user manuals, help screens, programs, and online tutorials includes data dictionary entries, data flow diagrams, screen layouts, and the systems request that initiated the program creates links within the program that will take a user to the appropriate documentation
Computers and Technology
1 answer:
valentinak56 [21]2 years ago
6 0

Answer:

In the given question the first line is correct, i.e. "Describes the inputs, outputs, and processing logic for all program modules".  

Explanation:

The documentation is a recorded text or image, which is preceding or in the code base of the programs, whether it describes how well the program works and how it is being used, and things in various positions can be influenced by people, and the wrong option can be described as follows:

  • In the documentation, it can't consist of rules and data.
  • In can't include a dictionary, flow maps, screen designs and device requests that began the program.
  • In can't provide links within the program.
You might be interested in
There are no breakpoints in the "Access Customer Account" subpage however there is an error. What will happen if you choose to s
blsea [12.9K]

Answer:

Move to the breakpoint at "Get Customer Details" stage.

Explanation:

This question is incomplete, we need a diagram and four options to resolve this questions, I attached the diagram and the options.

- The process will work all stages in the "Access Customer Account" page until the error is thrown and then focus would move to the breakpoint at "Get Customer Details" stage.

- The process will work all stages in the "Access Customer Account" page until the error is thrown and then focus would move to the "Recover1" stage.

- The process will work all stages in the "Access Customer Account" page until the error is thrown and then focus would move to the stage containing the error on the "Access Customer Account" page.

- The process will work all stages in the "Access Customer Account" page until the error is thrown and then focus would move to the "Exception1" stage.

In this case, we are going to run an extra from subpage testing in <u>Process studio</u>. Process studio is a tool where we can test these processes.

The process always it's going to work all stages in the "Access Customer Account" we're going to receive an interruption when the error is activated, moving the focus to the Get Customer Details stage.

There is an error in the stage Access Customer Account, if we run the processes with the Go button, the focus should move into the Recover1 stage, and should show the error.

But in this particular example, we must use the STEP OUT BUTTON, What means this?

The process it's going be executed, but won't show any error or message, because we have used the STEP OUT BUTTON.

If we use the STEP OUT BUTTON, the process should end but in this case, we have a breakpoint in Get Customer Details stage, for that the focus and the process will end in Get Customer Details stage and not at the end or at the Recover1 stage.

8 0
1 year ago
You are consulting for a trucking company that does a large amount ofbusiness shipping packages between New York and Boston. The
likoan [24]

Answer:

Answer explained with detail below

Explanation:

Consider the solution given by the greedy algorithm as a sequence of packages, here represented by indexes: 1, 2, 3, ... n. Each package i has a weight, w_i, and an assigned truck t_i. { t_i } is a non-decreasing sequence (as the k'th truck is sent out before anything is placed on the k+1'th truck). If t_n = m, that means our solution takes m trucks to send out the n packages.

If the greedy solution is non-optimal, then there exists another solution { t'_i }, with the same constraints, s.t. t'_n = m' < t_n = m.

Consider the optimal solution that matches the greedy solution as long as possible, so \for all i < k, t_i = t'_i, and t_k != t'_k.

t_k != t'_k => Either

1) t_k = 1 + t'_k

    i.e. the greedy solution switched trucks before the optimal solution.

    But the greedy solution only switches trucks when the current truck is full. Since t_i = t'_i i < k, the contents of the current truck after adding the k - 1'th package are identical for the greedy and the optimal solutions.

    So, if the greedy solution switched trucks, that means that the truck couldn't fit the k'th package, so the optimal solution must switch trucks as well.

    So this situation cannot arise.

  2) t'_k = 1 + t_k

     i.e. the optimal solution switches trucks before the greedy solution.

     Construct the sequence { t"_i } s.t.

       t"_i = t_i, i <= k

       t"_k = t'_i, i > k

     This is the same as the optimal solution, except package k has been moved from truck t'_k to truck (t'_k - 1). Truck t'_k cannot be overpacked, since it has one less packages than it did in the optimal solution, and truck (t'_k - 1)

     cannot be overpacked, since it has no more packages than it did in the greedy solution.

     So { t"_i } must be a valid solution. If k = n, then we may have decreased the number of trucks required, which is a contradiction of the optimality of { t'_i }. Otherwise, we did not increase the number of trucks, so we created an optimal solution that matches { t_i } longer than { t'_i } does, which is a contradiction of the definition of { t'_i }.

   So the greedy solution must be optimal.

6 0
2 years ago
Suppose your name was George Gershwin. Write a complete program that would print your last name, followed by a comma, followed b
NNADVOKAT [17]

Answer:

I will write the code in C++ and JAVA      

Explanation:

<h2>JAVA CODE</h2>

public class Main

{ public static void main(String[] args) {

       // displays Gershwin,George

     System.out.println("Gershwin,George"); }  }

<h2>C++ Code:</h2>

#include <iostream>

using namespace std;  

int main()

{  cout<<"Gershwin,George"; }    

// displays last name Gershwin followed by , followed by first name George

//displays Gershwin,George as output.

6 0
2 years ago
Read 2 more answers
You resurrected an old worksheet. It appears to contain most of the information that you need, but not all of it. Which step sho
shtirl [24]

Answer:

a)

Explanation:

Since the worksheet contains most of the data that you need, there is a decent possibility that it also contains the data that you are missing. Therefore, you should check for data you have previously hidden. Sometimes, some data in a worksheet may become irrelevant in a given moment, and instead of deleting it since it may be useful later most people tend to make that data hidden. So checking for previously hidden data may be the best solution in this scenario.

7 0
1 year ago
In this lab, you use the pseudocode in figure below to add code to a partially created Python program. When completed, college a
Elza [17]

Answer:

Python code is given below with appropriate comments

Explanation:

#Prompt the user to enter the test score and class rank.

testScore = input()

classRank = input()

#Convert test score and class rank to the integer values.

testScore = int(testScore)

classRank = int(classRank)

#If the test score is greater than or equal to 90.

if(testScore >= 90):

   #If the class rank is greater than or equal to 25,

   #then print accept message.

   if(classRank >= 25):

       print("Accept")

   

   #Otherwise, display reject message.

   else:

       print("Reject")

#Otherwise,

else:

   #If the test score is greater than or equal to 80.

   if(testScore >= 80):

       #If class rank is greater than or equal to 50,

       #then display accept message.

       if(classRank >= 50):

           print("Accept")

       

       #Otherwise, display reject message.

       else:

           print("Reject")

   

   #Otherwise,

   else:

       #If the test score is greater than or equal to

       #70.

       if(testScore >= 70):

           #If the class rank is greater than or equal

           #to 75, then display accept message.

           if(classRank >= 75):

               print("Accept")

           

           #Otherwise, display reject message.

           else:

               print("Reject")

       

       #Otherwise, display reject message.

       else:

           print("Reject")

4 0
2 years ago
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