Ask question

Ask question

All categories

2 years ago

11

Given is the array prices with 100 elements(prices[100]). The problem consists of two parts: 1. Find the highest price in the ar

ray; and 2. Reduce that price by 10% For any three numbers input by the user, output the numbers in ascending order.

Computers and Technology

1 answer:

Scrat [10]2 years ago

4 0

Answer:

1. Input array of 100 numbers

mx = 0

for (int i = 0; i < 100; i++)

if (arr[i] > mx)

mx = arr[i]

Output mx

2. Input array of 100 numbers

mx = 0

for (int i = 0; i < 100; i++)

if (arr[i] > mx)

mx = arr[i]

mx = mx * 0.9

3. Input three numbers

if(firstNumber > secondNumber) {

swap(firstNumber, secondNumber)

}

if (firstNumber > thirdNumber) {

swap(firstNumber, thirdNumber)

}

if (secondNumber > thirdNumber) {

swap(secondNumber, thirdNumber)

}

output firstNumber, secondNumber, thirdNumber

Explanation:

You might be interested in

_______________ is used by a hacker to mask intrusion and obtain administrator permissions to a computer.

Sergeu [11.5K]

Answer:

Rootkit.

Explanation:

Rootkit is a collection of software tools,mostly malicious.These are mostly used by hackers to obtain administrator permission to a computer by masking intrusion.

Root-kit is made from two word Root and kit.Where root refers to the name of privileged account on an operating system that is somewhat like unix and KIT refers to the tools used.

6 0

2 years ago

3.26 LAB: Leap Year A year in the modern Gregorian Calendar consists of 365 days. In reality, the earth takes longer to rotate a

Taya2010 [7]

Answer:

// program in C++ to check leap year.

// include header

#include<iostream>

using namespace std;

// main function

int main() {

// variable

int inp_year ;

// ask user to enter year

cout<<"Enter year:";

// read year

cin>>inp_year;

// check year is leap or not

if (((inp_year % 4 == 0) && (inp_year % 100 != 0)) || (inp_year % 400 == 0))

// if leap year , print leap year

cout<<inp_year<<" is a leap year.";

else

// print not leap year

cout<<inp_year<<" is not a leap year.";

return 0;

}

Explanation:

Read year from user.Then check if year is divisible by 4 and not divisible by 100 or year is divisible by 400 then year is leap year.otherwise year is not leap year.

Output:

Enter year:1712

1712 is a leap year.

6 0

2 years ago

Read 2 more answers

When an author produce an index for his or her book, the first step in this process is to decide which words should go into the

Igoryamba

Answer:

import string

dic = {}

book=open("book.txt","r")

# Iterate over each line in the book

for line in book.readlines():

tex = line

tex = tex.lower()

tex=tex.translate(str.maketrans('', '', string.punctuation))

new = tex.split()

for word in new:

if len(word) > 2:

if word not in dic.keys():

dic[word] = 1

else:

dic[word] = dic[word] + 1

for word in sorted(dic):

print(word, dic[word], '\n')

book.close()

Explanation:

The code above was written in python 3.

<em>import string </em>

Firstly, it is important to import all the modules that you will need. The string module was imported to allow us carry out special operations on strings.

<em>dic = {} </em>

<em>book=open("book.txt","r") </em>

<em> </em>

<em># Iterate over each line in the book</em>

<em>for line in book.readlines(): </em>

<em> </em>

<em> tex = line </em>

<em> tex = tex.lower() </em>

<em> tex=tex.translate(str.maketrans('', '', string.punctuation)) </em>

<em> new = tex.split() </em>

<em />

An empty dictionary is then created, a dictionary is needed to store both the word and the occurrences, with the word being the key and the occurrences being the value in a word : occurrence format.

Next, the file you want to read from is opened and then the code iterates over each line, punctuation and special characters are removed from the line and it is converted into a list of words that can be iterated over.

<em />

<em> </em><em>for word in new: </em>

<em> if len(word) > 2: </em>

<em> if word not in dic.keys(): </em>

<em> dic[word] = 1 </em>

<em> else: </em>

<em> dic[word] = dic[word] + 1 </em>

<em />

For every word in the new list, if the length of the word is greater than 2 and the word is not already in the dictionary, add the word to the dictionary and give it a value 1.

If the word is already in the dictionary increase the value by 1.

<em>for word in sorted(dic): </em>

<em> print(word, dic[word], '\n') </em>

<em>book.close()</em>

The dictionary is arranged alphabetically and with the keys(words) and printed out. Finally, the file is closed.

check attachment to see code in action.

7 0

2 years ago

The ____________ protocol enables two users to establish a secret key using a public-key scheme based on discrete logarithms

strojnjashka [21]

The answer in the space provided is the Diffie-Hellman Key Exchange. This is entitled to be the first published key algorithm in which has a limit in which the exchange occurs in secret values and that its purpose was to enable two users to have an exchange of key in a secure manner in means of using it for a subsequent symmetric encryption in terms of messages.

7 0

2 years ago

An attacker has been successfully modifying the purchase price of items purchased on the company's web site. The security admini

Kruka [31]

Answer:

Form the given statement i have come to know that the by changing hidden form values attacker has been able to modify the purchase price.

Explanation:

User can change a hidden field is not different from a common field from browser or server side.

If you want to store data then user must have to store them on server -side on a session and it is a fastest way.

8 0

2 years ago