Answer:
The correct answer is a increase in 3-phosphoglycerate levels and a decrease in RUBP levels.
Explanation:
NADPH is a reducing equivalent that is produced during light reaction of photosynthesis.The NADPH that is produced during light react is utilized in the dark reaction.
A decrease NADPH formation in the chroloplast will in turn decrease the formation of PGALD from phosphoglyceric acid(PGA).Some PGALD are used in the regeneration of ribulose bis phosphate(RUBP).
From this point of view it can be stated that decrease in NADPH level decreases PGALD level which in turn decreases RUBP levels.
As NADPH production is decreased in the chloroplast more phophoglyceric acid or 3-phosphoglycerate will accumulate thus the cellular level of PGA is increased.
The Yellowstone River ecosystem can support 2,300 bald eagles. This is an example of<u> temperate- zone ecosystems</u>
Explanation:
Yellowstone National Park is a natural paradise with over 70 species of birds,which include trumpeter swans, sandhill cranes, loons, peregrine falcons, osprey and bald eagles
The Greater Yellowstone Ecosystem, with Yellowstone at its core, is one of the largest nearly intact temperate- zone ecosystems on Earth. It has an area of 12–22 million acres; 18,750– 34,375 square miles
<u>Temperate ecosystems are the ecosystem that are characterized by the seasonality in temperature, with cooler winters and warmer summers, and also show various seasonality in precipitation patterns, resulting from seasonal changes in the orientation of Earth's axis relative to the sun.</u>
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The Yellowstone River ecosystem can support 2,300 bald eagles. This is an example of<u> temperate- zone ecosystems</u>
Hello there,
<span>A snake is about to eat some small eggs it has found in a bird's nest. A hawk swoops down and eats the snake. What is the role of the hawk?
I believe that your correct answer would be "</span><span>Tertiary consumer".
Hope this helps.
~Jurgen
</span>
Answer:
Explanation:
Narrow sense heritability - h2
selection differential - S
Selection differential is calculated from the difference between the population average and the parental population.
Breeder's equation:
Response to selection - R = h2S
Mean milk production of 10% cows for experiment = 8.9L/hr
Mean milk production of parental population = 5.1L/hr
Selection differential S= 8.9 - 5.1 = 3.8 L/hr
Response to selection = 0.587 × 3.8 = 2.23
Answer:
An endospore may survive a drought because it is protected by a THICK WALL
Explanation:
An endospore is a structure that is produced by some bacteria. This structure possesses characteristics such as:
a. Endospores have thick walls
b. They are very resistant and resilient to changes in temperature.
c. They are resistant as well to the action or activity of some chemicals.
d. Endospores serves as a means of protection for microorganisms such as Bacteria.
e. Endospores do not reproduce.
f. Endospores can be dormant or Inactive for a very long period of time.
Endospores may survive drought, activity of chemicals, extreme weather conditions, extreme temperatures due to the presence of thick walls in their structure.
