Answer:
the kidneys excrete salt into the urine when dietary salt levels rise
Explanation:
Hyponatremia is an electrolyte imbalance, with a low level of sodium in the blood. The normal value of sodium in adults is 136 to 145 mEq / L. Sodium is an element, or electrolyte of the blood. Sodium chloride is commonly known as table salt.
Certain conditions can cause decreased sodium in the blood. Specific causes of hyponatremia include:
Water poisoning (water replacement without electrolyte replacement).
Problems in the kidneys, heart or liver.
Medications: such as diuretics, Heparin, certain chemotherapeutics (Aminoglutethimide, Cyclophosphamide and Vincristine).
Conditions related to steroids, hormones or metabolic defects, such as a syndrome that alters the secretion of antidiuretic hormone (SSIHA). If this occurs, you urinate frequently and the kidneys excrete too much sodium. This can result from many conditions, including certain types of lung cancer.
The alula is a small structure that is found on birds. It is located at the joint between the hand wing and the arm wings of birds and it is the freely moving, first digit of a bird's wing. It is normally used by birds in slow flight. In humans, the structure that is comparable to the alula is the thumb.
Reproduction of a cell from an existing cell
Answer:
Cross each to a rabbit who you know is homozygous - i.e. a white rabbit. If there are any white offspring you know this is the heterozygote.
Explanation:
Heterozygous individuals are those with 2 different alleles of a gene. Homozygous individuals have have 2 alleles that are the same.
Imagine the allele for coat color is B black, or b white. If you cross 2 individuals who are homozygous for the black gene (BB), they would only produce black rabbits in the F1 (BB). If you cross the F1, they could only produce BB rabbits in the F2.
However, if you cross a heterozygous rabbit with a homozygous black rabbit (Bb x BB), you would get either BB or Bb rabbits in the F1. However, intercrossing them could produce BB, Bb, or bb rabbits. Therefore, white rabbits can be produced.
You know that white rabbits are bb. So if you are unsure about the genotype of the black rabbit, you can cross it with a white rabbit (either BB x bb or Bb x bb). If any white rabbits appear in the F1, you know there must be a b allele in the black rabbit genotype, so that rabbit must be heterozygous.
A patient is in need of hydration. Is likely in a hypertonic solution.
