He is making a plant cell since the cell walls are box shaped, the balloon would be the large vacuole which takes up a lot of space in the cell, the marbles would be the ribosomes.
Use the Hardy Weinburg
equation of allelic frequency.
P2+2pq+q2=1
174/1378 = 0.126 = q2
Therefore q2 = 0.126; q = 0.355
If q = 0.355 and we understand that p + q = 1, then
P = 1 – 0.355 = 0.645
To find homozygous dominant population (p2);
(0.645)2 x 1378 = 0.416 x 1378 = 573
Heterozygous popualiton (2pq);
(2 x 0.645 x 0.355) x 1378 = 0.458 x 1378= 631
Recessive indviduals (q2) = 174
Answer:
smooth endoplasmic reticulum
Explanation:
Smooth endoplasmic reticulum differs from the rough endoplasmic reticulum in not having ribosomes on its surface. The smooth endoplasmic reticulum (SER) extends from the rough ER and forms a network of membrane tubules. The function of the smooth ER is to serve as a site for the synthesis of lipids, fatty acids, and steroids such as estrogens and testosterone.
Enzymes for the synthesis of these diverse biomolecules are present in smooth ER. The smooth ER present in the muscle cells is called the sarcoplasmic reticulum. It stores the calcium ions which are released into the sarcoplasm of muscle cells during muscle contraction.