A sequential circuit has two inputs, w1and w2, and an output, z. Its function is to compare the input sequences on the two input
s. If w1= w2 during any three consecutive clock cycles, the circuit produces z= 1; otherwise, z= 0. The output should be equal to 1 in the same clock cycle when the third occurrence of w1= w2 is detected.
1 answer:
Answer / Explanation
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A sequential circuit has two inputs w1 and w2, and an output, z. Its function is to compare the
input sequences of the two inputs. If w1=w2 during any four consecutive clock cycles, the
circuit produces z=1; otherwise, z=0.
For example
w1:0110111000110
w2:1110101000111
z:0000100001110
Draw the state diagram using the minimum number of states.
Answer:
To properly answer this question, let us first define what a sequential circuit is, and input sequence.
To start with,a Sequential circuit can be defined or described as a type of circuit system used in the digital world most importantly in the digital theory of circuits. It is a type of circuit system whose output does not only depends on present values of input signals but also involves the sequence of one or more inputs and one or more outputs of the past whose realities are related.
Input sequence: This can be refereed to as the arranged pattern in which the data or values are imputed in the circuit.
If we now refer back to the question, we have
For grading each state:
+1 for each correct transition = 2 total per state
+2 for each correct output = 2 total per state
Total for every state = 4
Where the Maximum is 4*5 = 20
Hence,
If more than 5 states are used, but the logic is correct: +10 for the entire answer
Full credits for any other possible solution using 5 states.
We should also understand that : input labeled of (w1 =w2), (w1 == w2), (w1 XOR w2), 00,11 and similar also OK
We should also understand that : The solution here uses more machine. You can also use mealy machine. For mealy machine, only 4 states are enough. If you use 5 states we don’t deduct points.
So in summary, X = w1 XOR w2
Kindly find the required diagram below for proper clarity and understanding of the question.
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Answer: Inherent width in the emission line: 9.20 × 10⁻¹⁵ m or 9.20 fm
length of the photon emitted: 6.0 m
Explanation:
The emitted wavelength is 589 nm and the transition time is ∆t = 20 ns.
Recall the Heisenberg's uncertainty principle:-
∆t∆E ≈ h ( Planck's Constant)
The transition time ∆t corresponds to the energy that is ∆E
.
The corresponding uncertainty in the emitted frequency ∆v is:
∆v= ∆E/h = (5.273*10^-27 J)/(6.626*10^ J.s)= 7.958 × 10^6 s^-1
To find the corresponding spread in wavelength and hence the line width ∆λ, we can differentiate
λ = c/v
dλ/dv = -c/v² = -λ²/c
Therefore,
∆λ = (λ²/c)*(∆v) = {(589*10⁻⁹ m)²/(3.0*10⁸ m/s)} * (7.958*10⁶ s⁻¹)
= 9.20 × 10⁻¹⁵ m or 9.20 fm
The length of the photon (<em>l)</em> is
l = (light velocity) × (emission duration)
= (3.0 × 10⁸ m/s)(20 × 10⁻⁹ s) = 6.0 m
Answer:
1113kN
Explanation:
The ouside diameter OD of the pipe is 61cm and the thickness T is 0.9cm, so the inside diameter ID will be:
Inside Diameter = Outside Diameter - Thickness
Inside Diameter = 61cm - 0.9cm = 60.1cm
Converting this diameter to meters, we have:
This inside diameter is useful to calculate the volume V of water inside the pipe, that is the volume of a cylinder:
The problem gives you the water density d as 1.0kg/L, but we need to convert it to proper units, so:
Now, water density is given by the equation , where m is the water mass and V is the water volume. Solving the equation for water mass and replacing the values we have:
With the water mass we can find the weight of water:
Finally we find the total weight add up the weight of the water and the weight of the pipe,so:
Converting this total weight to kN, we have:
