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dybincka [34]
2 years ago
15

Drag the labels to their appropriate locations in the flowchart below, indicating the sequence of events in the production of fr

agment B. (Note that pol I stands for DNA polymerase I, and pol III stands for DNA polymerase III.)

Biology
1 answer:
matrenka [14]2 years ago
3 0

(Complete question attached)

Answer:

  1. Pol III binds to 3' end of primer B
  2. Poll III moves to 5' to 3',adding DNA nucleotides to primer B
  3. Pol I binds to 5' end primer A
  4. Pol I replaces primer A with DNA
  5. DNA ligase links fragments A and B

Explanation:

Both strands of parental DNA acts as a template for the synthesis of new DNA. The site of synthesis is called replication fork because the daughter strands look similar to <em>two-pronged fork.</em> The strands formed from Okazaki fragments(short sequences of DNA nucleotides) is called the <u>lagging strands,</u> which is synthesized in short fragments and in the opposite direction. While the strand that is synthesized continuously and in the same direction as the movement of the replication fork is called the <u>leading strand.</u> Both strands are synthesized in a 5'→3' direction. DNA ligase join these fragments together.

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Which of the following is the correct path a neural impulse will follow through the different layers of the retina? a. Rods and
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Answer:a. Rods and cones, bipolar cells, ganglion cells, optic nerve

Explanation:

The bipolar cells are present in between the rod and cone and ganglion cells.

The function of bipolar cells is to transmit signals from the photoreceptors (rod and cones cells) to the ganglion cells. The signals are then transferred to the brain via optic nerves where visual image is created.

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Imagine that a doctor is culturing two types of cells: one from a malignant melanoma and one from a normal skin sample. How woul
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Malignant melanoma cells would have active telomerases that constantly replenish and lengthen telomeres.

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What planet rotates from top to bottom?
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3 0
2 years ago
Read 2 more answers
1. Which word best describes a scientific hypothesis? a. provable b. theoretical c. testable d. quantifiable
Mekhanik [1.2K]
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2 years ago
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The state of health and functioning of the liver is often assessed with dye-tracer techniques. The dye used most frequently is b
elena-s [515]

Answer

1.Radioactive or chemical decay

2. X(t) = Xoe^-kt

lnY(t) = -t + lnYo

4. 6.07mg

Explanation:

Let the liver and and blood compartment be represented by the symbol L and B respectively

For the liver

Suppose a first Order removal process started with an amount X, in which amount b disappeared in time t, the process is decay process which can be represented as follows,

∫dX/dt = -K1X

By rearrangement and integration;

∫dX/X = -K1t

ln X = -K1t + C

Since At t= 0, X = Xo then

C = lnXo

The equation becomes:

lnX = -K1t + lnXo

lnX - lnXo = -K1t

ln(X/Xo) = -K1t

X/Xo = e^-kt

X(t) = Xoe^-kt

X(t) = Xoe^-0.5t........(2)

Similarly for B (blood), suppose a first order flow flow of the dye move from the blood to the liver, let Y be the initial concentration, and amount b that has flown to the liver in time t

B---------> B(t)

t=0 Yo 0

t=t. Y-b. b

dY/dt = -K12(Y-b)...........(3)

Let Y-b = Y(t)

∫dY/dt = -∫K12t

By rearrangement and integration;

∫dy/Y(t) = ∫-K12dt

lnY(t) = -K12t + C1

at t= 0, C1 = ln(Yo)

Therefore ln Y(t) = -K12t + lnYo

But K12 =1

ln Y(t) = -t + lnYo.............(4)

(3) The assumptions used here

is that of a decay for the liver . The amount remaining taking as the amount of a substance

(4) using the equation 2,

X(t)= Xo e^-K1t........(2)

For time t = 1hour, and an initial amount X = 10mg, K = 0.5

X(t) = 10× e^-0.5

X(t) = 10 × 0.607

X(t) = 6.07mg

(5) within the scope of information presented, I have no data to make this judgment.

3 0
2 years ago
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