Question

For the following code, if the input is negative, make numitemsPointer be null. Otherwise, make numitemsPointer point to numitems and multiply the value to which numitems Pointer points by 10.
Ex: If the user enters 99, the output should be: Items: 990
Code :
#include
int main(void) {
int* numItemsPointer;
int numItems;
scanf ("%d", &numItems);

/* Your solution goes here */

if (numItems Pointer == NULL) {
printf ("Items is negative\n");
}
else { printf("Items: %d\n", *numItemsPointer);
}
return 0;
}

Answer 1

Answer:

The program to this question can be described as follows:

Program:

#include <stdio.h> //defining header file  

int main() //defining main method

{

int* numItemsPointer; //defining pointer variable

int numItems; //defining integer variable

scanf ("%d", &numItems); //input value from user end

if(numItems < 0) //defining if block to check value

{

   numItemsPointer = NULL; //assign value to null

   printf ("Items is negative\n"); //print message

}

else //else block

{

   numItemsPointer = &numItems; //holds address

   numItems = numItems * 10; //multiple by 10

   printf("Items: %d\n", *numItemsPointer); //print value

}

return 0;

}

Output:

99

Items: 990

Explanation:

In the above program two integer variable "numItemsPointer and numItems" is defined, in which numItemsPointer is a pointer variable and numItems is integer variable, in which we input value from the user end, and an if condition statement is used, that check and calculate the values, which can be described as follows:

• In the if block a condition is defined that variable "numItems" is less then 0, if this condition is true so, inside the block, it will assign a value, that is equal to "NULL", and prints its value.
• If the condition is not true it will go to the else block, in this block, it will first pointer variable holds the variable address, and multiply the value by 10, and prints pointer variable value.

Answer 2

Answer:

hi

Explanation: