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2 years ago

When a machine on the public network wants to reach the server at 172.30.0.10, which ip will it use?

Computers and Technology

2 answers:

Kazeer [188]2 years ago

7 0

The IP address that it will use is 10.20.1.2

Further Explanation:

Computers connected to a network are assigned a unique number known as Internet Protocol (IP) Address.

IP (version 4) addresses consist of four numbers in the range 0-255 separated by periods (i.e. 127.0.0.1).

A computer may have either a permanent (static) IP address, or one that is dynamically assigned/leased to it. Most IP addresses can be mapped to host/domain names (i.e. www.speedguide.net).

Resolution between domain names and IP addresses is handled by Domain Name Servers (DNS).

10.20.1.2:

IP Address 10.20.1.2 is a private IP address. Private IP addresses are used inside a local area network (LAN).10.20.1.2 is an IPv4 address owned by Private network and located in , No unique . DNS records, DNS lookup 10.20.1.2 ... Geo location determines country, state and city of the IP address as well as latitude, longitude and altitude.

Warning : This is not a valid IP address on the Internet because it belongs to a information such as latitude/longitude, ISP details or threat level assessment.

Learn more:

Explain difference static IP address, Dynamic IP address

brainly.com/question/12502796

Keywords: IP address, LAN, DNS, ISP, protocol, computer

Anton [14]2 years ago

3 0

The IP address that it will use is 192.168.16.100

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1 year ago

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Locker doors There are n lockers in a hallway, numbered sequentially from 1 to n. Initially, all the locker doors are closed. Yo

kow [346]

Answer:

// here is code in C++

#include <bits/stdc++.h>

using namespace std;

// main function

int main()

{

// variables

int n,no_open=0;

cout<<"enter the number of lockers:";

// read the number of lockers

cin>>n;

// initialize all lockers with 0, 0 for locked and 1 for open

int lock[n]={};

// toggle the locks

// in each pass toggle every ith lock

// if open close it and vice versa

for(int i=1;i<=n;i++)

{

for(int a=0;a<n;a++)

{

if((a+1)%i==0)

{

if(lock[a]==0)

lock[a]=1;

else if(lock[a]==1)

lock[a]=0;

}

cout<<"After last pass status of all locks:"<<endl;

// print the status of all locks

for(int x=0;x<n;x++)

{

if(lock[x]==0)

{

cout<<"lock "<<x+1<<" is close."<<endl;

}

else if(lock[x]==1)

{

cout<<"lock "<<x+1<<" is open."<<endl;

// count the open locks

no_open++;

}

// print the open locks

cout<<"total open locks are :"<<no_open<<endl;

return 0;

}

Explanation:

First read the number of lockers from user.Create an array of size n, and make all the locks closed.Then run a for loop to toggle locks.In pass i, toggle every ith lock.If lock is open then close it and vice versa.After the last pass print the status of each lock and print count of open locks.

Output:

enter the number of lockers:9

After last pass status of all locks:

lock 1 is open.

lock 2 is close.

lock 3 is close.

lock 4 is open.

lock 5 is close.

lock 6 is close.

lock 7 is close.

lock 8 is close.

lock 9 is open.

total open locks are :3

5 0

1 year ago

Assume that processor refers to an object that provides a void method named process that takes no arguments. As it happens, the

Gnom [1K]

Answer:

Following are the code in the Java Programming Language:

try{ //try block.

processor.process(); // call the function through the object.

}

catch(Exception e){ //catch block .

System.out.println( "process failure"); //if any exception occurs then print.

}

Explanation:

In the following code, we set two blocks in Java Programming Language of the exception handling which is try block or catch block.

In try block we call the function "process()" through the "processor" object.
If any exception occurs in the program then the catch block print the following message is "process failure"

6 0

1 year ago

Find a 95% confidence interval for the mean failure pressure for this type of roof panel.The article "Wind-Uplift Capacity of Re

aliya0001 [1]

Answer:

The 95% confidence interval would be given by (2.351;3.525)

Explanation:

1) Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X$ represent the sample mean

$\mu$ population mean (variable of interest)

s represent the sample standard deviation

n represent the sample size

2) Confidence interval

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

In order to calculate the mean and the sample deviation we can use the following formulas:

$\bar X= \sum_{i=1}^n \frac{x_i}{n}$ (2)

$s=\sqrt{\frac{\sum_{i=1}^n (x_i-\bar X)}{n-1}}$ (3)

The mean calculated for this case is $\bar X=2.938$

The sample deviation calculated $s=0.472$

In order to calculate the critical value $t_{\alpha/2}$ we need to find first the degrees of freedom, given by:

$df=n-1=5-1=4$

Since the Confidence is 0.95 or 95%, the value of $\alpha=0.05$ and $\alpha/2 =0.025$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.025,4)".And we see that $t_{\alpha/2}=2.78$

Now we have everything in order to replace into formula (1):

$2.938-2.78\frac{0.472}{\sqrt{5}}=2.351$

$2.938+2.78\frac{0.472}{\sqrt{5}}=3.525$

So on this case the 95% confidence interval would be given by (2.351;3.525)

5 0

1 year ago