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2 years ago

When a machine on the public network wants to reach the server at 172.30.0.10, which ip will it use?

Computers and Technology

2 answers:

Kazeer [188]2 years ago

7 0

The IP address that it will use is 10.20.1.2

Further Explanation:

Computers connected to a network are assigned a unique number known as Internet Protocol (IP) Address.

IP (version 4) addresses consist of four numbers in the range 0-255 separated by periods (i.e. 127.0.0.1).

A computer may have either a permanent (static) IP address, or one that is dynamically assigned/leased to it. Most IP addresses can be mapped to host/domain names (i.e. www.speedguide.net).

Resolution between domain names and IP addresses is handled by Domain Name Servers (DNS).

10.20.1.2:

IP Address 10.20.1.2 is a private IP address. Private IP addresses are used inside a local area network (LAN).10.20.1.2 is an IPv4 address owned by Private network and located in , No unique . DNS records, DNS lookup 10.20.1.2 ... Geo location determines country, state and city of the IP address as well as latitude, longitude and altitude.

Warning : This is not a valid IP address on the Internet because it belongs to a information such as latitude/longitude, ISP details or threat level assessment.

Learn more:

Explain difference static IP address, Dynamic IP address

brainly.com/question/12502796

Keywords: IP address, LAN, DNS, ISP, protocol, computer

Anton [14]2 years ago

3 0

The IP address that it will use is 192.168.16.100

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2 years ago

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valentina_108 [34]

Answer:

Kanban System

Explanation:

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2 years ago

7.8.1: Function pass by reference: Transforming coordinates. Define a function CoordTransform() that transforms the function's f

Lilit [14]

Answer:

Here is the CoordTransform() function:

void CoordTransform(int xVal, int yVal, int &xValNew, int &yValNew){

xValNew = (xVal + 1) * 2;

yValNew = (yVal + 1) * 2; }

The above method has four parameters xVal and yVal that are used as input parameters and xValNew yValNew as output parameters. This function returns void and transforms its first two input parameters xVal and yVal into two output parameters xValNew and yValNew according to the formula: new = (old + 1) *

Here new variables are xValNew and yValNew and old is represented by xVal and yVal.

Here the variables xValNew and yValNew are passed by reference which means any change made to these variables will be reflected in main(). Whereas variables xVal and yVal are passed by value.

Explanation:

Here is the complete program:

#include <iostream>

using namespace std;

void CoordTransform(int xVal, int yVal, int &xValNew, int &yValNew){

xValNew = (xVal + 1) * 2;

yValNew = (yVal + 1) * 2;}

int main()

{ int xValNew;

int yValNew;

int xValUser;

int yValUser;

cin >> xValUser;

cin >> yValUser;

CoordTransform(xValUser, yValUser, xValNew, yValNew);

cout << "(" << xValUser << ", " << yValUser << ") becomes (" << xValNew << ", " << yValNew << ")" << endl;

return 0; }

The output is given in the attached screenshot

7 0

2 years ago

Read first a user's given name followed by the user's age from standard input. Then use an ofstream object named outdata to writ

Stells [14]

Answer:

* Program to write data to text file.

#include<iostream>

#include<fstream>

#include<string.h>

using namespace std;

int main()

{

//Variable to name and age of a person.

string name;

int age;

cout<<"Enter your name"<<endl;

cin>>name;

cout<<"Enter your age"<<endl;

cin>>age;

//Creating object of ofstream.

ofstream file;

file.open ("outdata.txt");

//Writing data to file named outdata.txt

file<<name<<" "<<age;

file.close();

}

Output:

Enter your name

John

Enter your age

Content of Output.txt:

John 25

Explanation:

To write data to a file ofstream object is used. An ofstream object file is created first and then using this object a file named "outdata.txt" is created.

Finally using shift operator (<<), by means of operator overloading, name and age of person is transferred to file outdata.txt.

8 0

2 years ago

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LUCKY_DIMON [66]

Answer:

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2 years ago