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1 year ago

A teacher brings 3 gallons of juice on a field trip. There are 36 students on the trip.

1 answer:

4 0

There are 384 fluid ounces in 3 gallons. The teacher does not have enough for each student to have 12 fluid ounces.

384÷12=32

4 students would go thirsty.

You might be interested in

You are a dog breeder and are interested in two traits that you believe are inherited by simple genetic loci glossy (G) coat is

Paul [167]

Answer:

GL, Gl, gL, and gl

Explanation:

The mom is glossy long haired. Since glossy (G) is dominant over to dull (g) and long hair (L) is dominant to short hair (l), the possible genotypes of the mom would be:

GGLL, GgLL, GGLl, or GgLl

The dad is dull and short haired, the genotype would be ggll.

GGLL x ggll

Progeny = all GgLl (all glossy long haired)

GgLL x ggll

Progeny = 8 GgLl, 8 ggLi (glossy long haired and dull long haired)

GGLl x ggll

Progeny = 8 GgLl, 8 Ggll (glossy long haired and glossy short haired)

GgLl x ggll

Progeny = 4 GgLl, 4 Ggll, 4 ggLl, 4 ggll (glossy long, glossy short, dull long, and dull short)

<em>Only a cross of ggll with GgLl produced the offspring that cover the phenotypic range shown in the illustration. Hence, the genotype of the mom is GgLl.</em>

The parental gametes produced by the mom would be; GL, Gl, gL, and gl

5 0

1 year ago

Two autosomal genes, J and K, are 60 map units apart. You perform the following testcross: J K / j k x j k / j k. At what freque

Dmitry [639]

Answer:

J K / j k = 20%

j k / j k = 20%

J k / j k = 30%

j K / j k = 30%

Explanation:

To calculate the recombination frequency, we have to know that 1% of recombinations = 1 map unit = 1cm. And that the maximum recombination frequency is always 50%.

The map unit is the distance between the pair of genes for which every 100 meiotic products, one of them results in a recombinant one.

So, en the exposed example:

J and K are autosomal genes

J and K are separated by 60 M.U.

60 M.U. means that there is 60% of recombination.

Cross) J K / j k x j k / j k

Gametes) JK Parental jk, jk, jk, jk

jk Parental

Jk Recombinant

jK Recombinant

One map unit equals 1% of recombination frequency. This means that every 100 meiotic products, one of them is a recombinant one.

1 M.U. -------------- 1% recombination

60 M.U. ------------ 60% recombination

30% Jk + 30% jK

100 M.U. - 60 M.U. = 40 M.U.

40M.U.--------------40 % Parental (Not recombinant)

20% JK + 20% jk

Punnet Square) JK jk Jk jK

jk JK/jk jk/jk Jk/jk jK/jk

J K / j k = 20%

j k / j k = 20%

J k / j k = 30%

j K / j k = 30%

3 0

1 year ago

There is a phenomenon called paternal leakage in which a small amount of the mitochondrial DNA from the father is found in the o

Lady bird [3.3K]

Answer:

Maternal inheritance means the transfer of characters from mothers to offspring through mitochondria. The paternal leakage means some mitochondria transfer from the father as well.

As the information given in the question, the amount of DNA from father's mitochondria is small. The quite small amount of DNA will not affect the conclusions and results that are made by the studies and do not affect the inheritance of mitochondrial DNA.

4 0

2 years ago

A botanist created a linear model to predict plant height from soil acidity (pH level) for a certain type of plant. The slope of

Nutka1998 [239]

Answer:

0.625

Explanation:

The slope (m) of a linear regression line is ...

$m=r_{xy}\cdot\dfrac{s_y}{s_x}$