Answer:Archaea, Bacteria, and Eukarya
Explanation:
The hormones that stimulate the breakdown of liver glycogen are epinephrine and glucagon. Epinephrine is the one that triggers the glycogen breakdown inside the muscle and also inside the liver. However, the liver is the one that is more active or responsive to the hormone called glucagon than the muscles. A glucagon is a hormone which is a polypeptide hidden by the cells of our pancreas called α cells whenever our blood-sugar is low. This hormone indicates the state of starving.
Answer:
p = 0.34
Explanation:
The green allele is recessive, meaning two copies of q (qq) are required to be green. Conversely, animals that are either pp or pq will be blue.
If 44 organisms are green, that means 44 are qq.
For genotype frequencies, the equation is:
homozygous dominant genotype + heterozygous + homozygous recessive = 100%
Which is denoted as
p² + 2pq + q² = 1
We know that q² = 44/100 = 0.44
To work out q, we can do 
= 0.66
For allele frequencies, the total must add up to 100%, so
p + q =1
We know that q= 0.66
So p = 0.34, because 0.66 + 0.34 = 1
Answer:
Genotypic and Phenotypic ratios → 1:1:1:1
- 25% of the progeny is expected to be SsWw, exhibiting spotted skin and wooly hair, SsWw
- 25% of the progeny is expected to be Ssww, exhibiting spotted skin and non-wooly hair, Ssww
- 25% of the progeny is expected to be ssWw, exhibiting non- spotted skin and wooly hair, ssWw
- 25% of the progeny is expected to be ssww, exhibiting non-spotted skin and non-wooly hair, ssww
Explanation:
<u>Available data</u>:
- spotted skin (S) is dominant over non-spotted skin (s)
- wooly hair (W) is dominant over non-wooly hair (w)
- Cross: heterozygous spotted, non-wooly mammoth with a heterozygous wooly-haired, non-spotted mammoth.
Parentals) Ssww x ssWw
Gametes) Sw, Sw, sw, sw
sW, sW, sw, sw
Punnett square) Sw Sw sw sw
sW SsWw SsWw ssWw ssWw
sW SsWw SsWw ssWw ssWw
sw Ssww Ssww ssww ssww
sw Ssww Ssww ssww ssww
F1) 4/16 = 1/4 = 25% of the progeny is expected to be SsWw, exhibiting spotted skin and wooly hair
4/16 = 1/4 = 25% of the progeny is expected to be Ssww, exhibiting spotted skin and non-wooly hair
4/16 = 1/4 = 25% of the progeny is expected to be ssWw, exhibiting non- spotted skin and wooly hair
4/16 = 1/4 = 25% of the progeny is expected to be ssww, exhibiting non-spotted skin and non-wooly hair.
Genotypic and Phenotypic ratios → 1:1:1:1
Answer:
Option B
Explanation:
Complete question -
Following their sixteen-week, closed-ended, grief and loss psychotherapy group with adults as reported by Price et al, which of Yalom's therapeutic factors was most identifiable?
a. recapitulation
b. altruism
c. universality
d. imagery
Solutions -
Out of the eleven therapeutic factors the one that will be easily recognizable will be the one which will involve some kind of action and interaction or any visible signs. Altruism would affect a person positively and help him/her to gain confidence. This confidence will be visible by the person’s action when he/she will help other people in the group to gain value and significance in the same way as he/she has done.
Hence, option B is correct
