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GarryVolchara [31]
2 years ago
6

swenson Saws produces bows, frame, dovetail, and tenon saws used by craft furniture makers. During an 8-hour shift, a saw is pro

duced every 6 minutes. The demand for the bow, frame, and dovetail saws is about the same, but the demand tenon saw is twice the demand for the other three. a) If mixed-model scheduling is used, how many of each saw will be produced before the cycle is repeated? b) determine a satisfactory production sequence for one unit production. How often is this sequence repeated? c) how many of each saw does Swenson produce in one shift?
Business
2 answers:
RUDIKE [14]2 years ago
7 0

Answer:

Given: Total shift time = 8 hours = 8 * 60 = 480 minutes

time required for production of one saw = 6 minutes

Demand for Bow saw = Demand for frame saw = Demand for dovetail saw = 1/2 * Demand of Tenon saw

a) Mixed model schedule:

Mixed model schedule

Product no. per batch

Bow Saw 1

Frame Saw 1

Dovetail Saw 1

Tenon Saw 2

Total 5

Therefore 2 Tenon Saw, and each bow, frame, and dovetail saws will be produced before the cycle is repeated.

b) 2 Tenon Saw, 1 bow, 1 frame, and 1 dovetail saws will be produced under production sequence for one unit production.

The length of cycle will be 5*6=30 minutes i.e. the cycle will repeat once in 30 minutes for 8 hours means totally it will repeat 16 times during one shift.

c) Number of saws Swenson produce in one shift = Number of Bow saw Swenson produce in one shift + Number of Frame saw Swenson produce in one shift + Number of Dovetail saw Swenson produce in one shift + Number of Tenon saw Swenson produce in one shift

Explanation:

gavmur [86]2 years ago
3 0

Answer:

Given: Total shift time = 8 hours = 8 * 60 = 480 minutes

time required for production of one saw = 6 minute

Demand for Bow saw = Demand for frame saw = Demand for dovetail saw = 1/2 * Demand of Tenon saw

a) Mixed model schedule:  

                       Mixed model schedule

Product                      no. per batch

Bow Saw                            1

Frame Saw                    1

Dovetail Saw                    1

Tenon Saw                    2

Total                            5

Therefore 2 Tenon Saw, and each bow, frame, and dovetail saws will be produced before the cycle is repeated.

b) 2 Tenon Saw, 1 bow, 1 frame, and 1 dovetail saws will be produced under production sequence for one unit production.

The length of cycle will be 5*6=30 minutes i.e. the cycle will repeat once in 30 minutes for 8 hours means totally it will repeat 16 times during one shift.

c)  Number of saws Swenson produce in one shift = Number of Bow saw Swenson produce in one shift + Number of Frame saw Swenson produce in one shift + Number of Dovetail saw Swenson produce in one shift + Number of Tenon saw Swenson produce in one shift

Number of saws Swenson produce in one shift = 480\div 30\times 1 + 480\div 30\times 1 + 480\div 30\times 1 + 480\div 30\times 2 = 16 + 16 + 16 + 32 = 80 saws per shift

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            For number of employees: Z = 2.92

  • b) Lacation of the two Z values: see the pitcture attached

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            - Clarion's number of employess is greater than the average number of employees of the other fabricators.

Explanation:

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For the number of employees, the mean is 1,500 and the standard deviation is 120.

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The Z-value or Z-score of a normal variable is the normalized mean. It tells how many standard deviations a value is away from the mean.

The formula to calculate the Z-value is

          Z-value=\dfrac{x-\mu}{\sigma}

Where:

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For the net sales:

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<u><em>b. Locate the two z values. </em></u>

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I have attached a figure with both Z-values located. Look at the attached pitcures.

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Answer:

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