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Fantom [35]
2 years ago
14

Read_file = open('numbers.txt', 'r')

Computers and Technology
1 answer:
Svetradugi [14.3K]2 years ago
4 0

Answer:

To do that, use exception handling

Explanation:

Try:

    read_file = open('numbers.txt', 'r')

    file_numbers = read_file.read()

except  IOError exceptions:

    print("Trouble opening file. Try again")

    read_file.close()

list_values = file_numbers.split()

list_length = len(list_values)

for i in range(list_length):

list_values[i] = float(list_values[i])

except ValueError:

    print("File must have  only numbers. Try again.")

List_sum = sum(list_values)

Average_value = (List_sum)/list_length

print(Average_value)

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Describe a strategy for avoiding nested conditionals. Give your own example of a nested conditional that can be modified to beco
harina [27]

Answer:

One of the strategies to avoid nested conditional is to use logical expressions such as the use of AND & operator.

One strategy is to use an  interface class with a method. That method can be created to be used for a common functionality or purpose. This is also called strategy design pattern. You can move the chunk of conditional statement to that method. Then each class can implement that interface class and use that shared method according to their own required task by creating objects of sub classes and call that common method for any such object. This is called polymorphism.

Explanation:

Nested conditionals refers to the use of if or else if statement inside another if or else if statement or you can simply say a condition inside another condition. For example:

if( condition1) {  

//executes when condition1 evaluates to true

 if(condition2) {

//executes when condition1  and condition2 evaluate to true

 }  else if(condition3) {

 //when condition1 is true and condition3 is true

} else {

 //condition1  is true but neither condition2 nor conditions3 are true

}  }

The deeply nested conditionals make the program difficult to understand or read if the nested conditionals are not indented properly. Also the debugging gets difficult when the program has a lot of nested conditionals.

So in order to avoid nested conditionals some strategies are used such as using a switch statement.

Here i will give an example of one of the strategies i have mentioned in the answer.

Using Logical Expressions:

A strategy to avoid nested conditionals is to use logical expressions with logical operators such as AND operator. The above described example of nested conditionals can be written as:

if(condition1 && condition2){  //this executes only when both condition1 and condition2 are true

} else if(condition1 && condition3) {

this executes only when both condition1 and condition3 are true

} else if(condition1 ){

//condition1  is true but neither condtion2 nor condtion3 are true  }

This can further be modified to one conditional as:

if(!condition3){

// when  condition1 and condition2 are true

}

else

// condition3 is true

Now lets take a simple example of deciding to go to school or not based on some conditions.

if (temperature< 40){

  if (busArrived=="yes")   {

      if (!sick)       {

          if (homework=="done")           {

              printf("Go to school.");

          }

      }     

  }

}

This uses nested conditionals. This can be changed to a single conditional using AND logical operator.

if ((temperature <40) && (busArrived=="yes") &&

(!sick) && (homework=="done"))

{    cout<<"Go to school."; }

6 0
2 years ago
Write an if-else statement that displays 'Speed is normal' if the speed variable is within the range of 24 to 56. If the speed v
kari74 [83]

Answer:

import java.util.Scanner;

public class Speed{

int speed;

public Speed(int speed){

this.speed = speed;

}

public void checkSpeed(){

if(speed >= 24 || speed <= 56){

System.out.println("Speed is normal");

}

else

System.out.println("Speed is abnormal");

}

public static void main(String...args){

Scanner input = new Scanner(System.in);

int userSpeed = 0;

System.out.println("Enter a speed: ");

userSpeed = input.nextInt();

Speed obj1 = new Speed(userSpeed)

obj1.checkSpeed();

}

Explanation:

4 0
2 years ago
A communication pattern in which the parties slowly reduce their dependence on one another, withdraw, and become less invested i
zepelin [54]

Answer:

The correct answer to the following question is option A. an avoidance spiral.

Explanation:

An avoidance spiral is a spiral in which parties avoid the conflicts at all cost in which leads to reducing the influence, dependence, etc. This spiral can also be destructive.

In other words, it is the only spiral in parties slowly reduces their dependence and the influence on the one and another.

7 0
2 years ago
Read the attached paper titled A Survey of Coarse-Grained Reconfigurable Architecture and comment on it. Make sure to specifical
Pani-rosa [81]

Answer:

lol

Explanation:

I NEED POINTS

5 0
1 year ago
Write a program that uses the function isPalindrome given in Example 6-6 (Palindrome). Test your program on the following string
Artist 52 [7]

Answer:

#include <bits/stdc++.h>

using namespace std;

bool isPalindrome(string str)

{

   char a,b;

int length = str.length();

for (int i = 0; i < length / 2; i++)

{

   a=tolower(str[i]);//Converting both first characters to lowercase..

   b=tolower(str[length-1-i]);

   if (b != a )

return false;

}

return true;

   

}

int main() {

   string t1;

   cin>>t1;

   if(isPalindrome(t1))

   cout<<"The string is Palindrome"<<endl;

   else

   cout<<"The string is not Palindrome"<<endl;

return 0;

}

Output:-

Enter the string

madam

The string is Palindrome

Enter the string

abba

The string is Palindrome

Enter the string

22

The string is Palindrome

Enter the string

67876

The string is Palindrome

Enter the string

444244

The string is not Palindrome

Explanation:

To ignore the cases of uppercase and lower case i have converted every character to lowercase then checking each character.You can convert to uppercase also that will also work.

6 0
2 years ago
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