Answer:
- If a group of 9 kids have won a total of 100 trophies, then at least one of the 9 kids has won at least 12 trophies.
- If a person buys at least 400 cups of coffee in a year, then there is at least one day in which the person has bought at least two cups of coffee.
- The average of three real numbers is greater than or equal to at least one of the numbers.
Explanation:
1)
Suppose that each kid has less than 12 trophies
Total trophies = 100
Maximum trophies won by one kid = 11
total kids = 9
total number of trophies = 9 * 11 = 99 which contradicts the fact the total number of trophies are 100
2)
Suppose that person has less than 2 cups of coffee a day
Total cups of coffee = 400
he has bought at least one cup of coffee each day
which means
total number of cups of coffee = 1* 366 = 366 which contradicts the fact the person buys at least 400 cups of coffee in a year
3)
Average of three number = (a+ b+ c)/3
suppose that there are real numbers a, b, and c such that all three numbers are less than the average of the three numbers.
Let m be the average (a+b+c
)/3 = m. Then our assumption states that (a < m) and (b < m) and (c < m). By adding all the inequalities we get a + b + c < 3m. But m is defined to be (a+b+c)
/3 , so a + b + c = 3m. But now we have that 3m = a + b + c < 3m. So 3m < 3m which is an obvious contradiction. Thus our claim is true
Answer:
stress about paying bills
a lack of money for other expenses
great electronic connectivity
Explanation:
The Maya classic period has seen the rise of conspicuous and mass consumption. In the given scenario all the expense her paid by credit cards and cash is rarely used. There will be a stress for paying bills. There will be lack of money available in hand for some routine expenses and mandatory purchases. It gives a great electronic connectivity. All the funds are considered as safe.
Answer:
The answer is the last option
Answer:
identifying/acknowledging
Explanation:
