Answer:
When ROM receives power, its ROM BIOS instructions are activated and they load the operating system into RAM. This startup sequence is referred to as the boot process. After the operating system is loaded, the computer can accept input, display output, run software, and access your data.
<span>Looking at the first two vertices, A and B, we see that the x values have a difference of (-1 - 13) units, or 14 units. This gives us the base of the parallelogram. Next, we look at the difference between the y values between B and C to find the height. In this case, they are (12 - [-5] ) units, or 17 units. The area of a parallelogram is simply base multiplied by height, which is (14 * 17), or 238 square units.</span>
Answer:
Calculate the average processing time of the new software
Explanation:
Since the average processing time of the old software is already known, the simplest test to see if the new software is faster than the old software will be to calculate the average processing time for the new software and compare it with the average processing time of the old software.
If the new software have an average processing time lower/smaller than that of the old software; we conclude that the new software is faster.
If the new software have an average processing time higher/larger than that of the old software; we conclude that the old software is faster.
Answer:
<u>The total time elapsed from the time a bit is created (from the original analog signal at Host A) until the bit is decoded (as part of the analog signal at Host B is </u><u>25.11 ms</u>
Explanation:
Host A first converts the analog signal to a digital 64kbps stream and then groups it into 56-byte packets. The time taken for this can be calculated as:
time taken 1= 
= (56 x 8) bits / 64 x 10³ bits/s
= 7 x 10⁻³s
time taken 1= 7 ms
The transmission rate of the packet from Host A to Host B is 4 Mbps. The time taken to transfer the packets can be calculated as:
time taken 2= (56 x 8) bits / 4 x 10⁶ bits/s
= 1.12 x 10⁻⁴ s
time taken 2= 112 μs
The propagation delay is 18 ms.
To calculate the total time elapsed, we need to add up all the time taken at each individual stage.
<u />
<u> = Time taken 1 + Time taken 2 + Propagation Delay</u>
= 7 ms + 112 μs + 18 ms
= 0.025112 s
= 25.11 ms
