== is an operator that returns a boolean if both operand are equal.
1101 * 10 is 11010
11000 + 10 is 11010
11010 == 11010
Thus the output would be True.
Answer:
e) Code segment II produces correct output for all values of str, but code segment I produces correct output only for values of str that contain "pea" but not "pear".
Explanation:
<em>if - elseif - else statements work in sequence in which they are written. </em>
- <em> </em>In case <em>if() statement is true, </em>else if() and else statements will not get executed.
- In case <em>else if() statement is true</em>, conditions in if() and else if() will be checked and else statement will not be executed.
- In case <em>if() and else if() both are false</em>, else statement will be executed<em>.</em>
First, let us consider code segment I.
In this, first of all "pea" is checked in if() statement which will look for "pea" only in the String str. So, even if "pearl" or "pear" or "pea" is present in 'str' the result will be true and "pea" will get printed always.
After that there are else if() and else statements which will not get executed because if() statement was already true. As a result else if() and else statements will be skipped.
Now, let us consider code segment II.
In this, "pearl" is checked in if() condition, so it will result in desired output.
Executable code is attached hereby.
Correct option is (e).
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Answer:
Big Oh notation is used to asymptotically bound the growth of running time above and below the constant factor.
Big Oh notation is used to describe time complexity, execution time of an algorithm.
Big Oh describes the worst case to describe time complexity.
For the equation; T(N) = 10000*N + 0.00001*N^3.
To calculate first of all discard all th constants.
And therefore; worst case is the O(N^3).
The telecommunications device that is widely used in industries that require closed communication are walkie-talkies. Correct answer: D
Walkie-talkies are hand-held, portable, two-way radio transceivers which enable secure communication between the two points, without being part of a network.