Answer:
Big Oh notation is used to asymptotically bound the growth of running time above and below the constant factor.
Big Oh notation is used to describe time complexity, execution time of an algorithm.
Big Oh describes the worst case to describe time complexity.
For the equation; T(N) = 10000*N + 0.00001*N^3.
To calculate first of all discard all th constants.
And therefore; worst case is the O(N^3).
Answer:
- public class FindDuplicate{
-
- public static void main(String[] args) {
- Scanner input = new Scanner(System.in);
-
- int n = 5;
- int arr[] = new int[n];
-
- for(int i=0; i < arr.length; i++){
- int inputNum = input.nextInt();
- if(inputNum >=1 && inputNum <=n) {
- arr[i] = inputNum;
- }
- }
-
- for(int j =0; j < arr.length; j++){
- for(int k = 0; k < arr.length; k++){
- if(j == k){
- continue;
- }else{
- if(arr[j] == arr[k]){
- System.out.println("True");
- return;
- }
- }
- }
- }
- System.out.println("False");
- }
- }
Explanation:
Firstly, create a Scanner object to get user input (Line 4).
Next, create an array with n-size (Line 7) and then create a for-loop to get user repeatedly enter an integer and assign the input value to the array (Line 9 - 14).
Next, create a double layer for-loop to check the each element in the array against the other elements to see if there is any duplication detected and display "True" (Line 21 - 22). If duplication is found the program will display True and terminate the whole program using return (Line 23). The condition set in Line 18 is to ensure the comparison is not between the same element.
If all the elements in the array are unique the if block (Line 21 - 23) won't run and it will proceed to Line 28 to display message "False".
Answer:(c) abstract class A { abstract void unfinished(); }
Explanation:
A legal abstract class must have the keyword abstract before the class and an abstract class has abstract functions with the keyword abstract written and a void as the return type.
Answer:
Following are the code:
Code:
total = 0; //assign value to total variable.
for (int i=0; i<x.length; i++) //for loop
{
total=total+x[i]; //add all array elements in total variable.
}
Explanation:
In the following question, it is defined that x and total is variable. Where variable x is an integer type array and total is an integer variable. we define some code for calculating the sum of the array element. In the above code, we use for loop that calculates sum of array elements that can be described as:
- To calculate the sum we use the total variable. In total variable, we assign value 0.
- Then we define for loop in loop we use total variables that add all array (x[]) elements.