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AnnyKZ [126]
1 year ago
7

PLEASE HELP!!~~

Computers and Technology
1 answer:
Law Incorporation [45]1 year ago
7 0

Answer:

A

Explanation:

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Does the submission include the file "SuperPower.java"? Does the file include a public class called "SuperPower"? Does the class
Oduvanchick [21]

Answer:    

Here is the program fulfilling all the requirements given:

import javax.swing.JOptionPane;      

public class SuperPower{

public static void main(String[] args) {

String power;

power = JOptionPane.showInputDialog("What is your super power?");

power = power.toUpperCase();

JOptionPane.showMessageDialog(null, power);} }

Explanation:

Does the file include a public class called "SuperPower"

See the statement:

public class SuperPower

Does the class include a public method called "main"? Is the "main" method static?

See the statement:

public static void main(String[] args)

Does the main method have a String assignment statement that uses "JOptionPane.showInputDialog"

See the statement:

power = JOptionPane.showInputDialog("What is your super power?");

Does the main method have a statement that uses "JOptionPane.showMessageDialog"?

See the statement:

JOptionPane.showMessageDialog(null, power);

Does the program convert the String from "JOptionPane.showInputDialog" using the "toUpperCase" method?

See the statement:

power = power.toUpperCase();

Does the submission include a screenshot that shows an Input dialog that asks, "What is your superpower?" Does the submission include a screenshot that shows a Message dialog stating " TO THE RESCUE!", where "" is the input converted to upper case?

See the attached screenshots

If the program does not let you enter an exclamation mark after "to the rescue" then you can alter the code as follows:

import javax.swing.JOptionPane;

public class SuperPower{

public static void main(String[] args) {

String power;

power = JOptionPane.showInputDialog("What is your super power?");

power = power.toUpperCase();

JOptionPane.showMessageDialog( null, power+"!");} } // here just add an exclamation mark which will add ! after the string stored in  power

5 0
2 years ago
Assume that month is an int variable whose value is 1 or 2 or 3 or 5 ... or 11 or 12. Write an expression whose value is "jan" o
Tamiku [17]

Answer:

The code is given below

Explanation:

The correct syntax would be to place appropriate parenthesis.

(month==1?"jan":(month==2?"feb":(month==3?"mar":(month==4?"apr":(month==5?"may":(month==6?"jun":(month==7?"jul":(month==8?"aug":(month==9?"sep":(month==10?"oct":(month==11?"nov":"dec")))))))))));

Similarly, you can also use the following code:

String[] months = { "jan", "feb", "mar", "apr", "may", "jun", "jul", "aug", "sep", "oct", "nov", "dec" };

int month = 1;

String monthDescription = months[month - 1];

7 0
2 years ago
An expression containing the operator && is true either or both of its operands are true. True/False
Luba_88 [7]

Answer:

True.

Explanation:

An expression containing the && and  operator is only true if both of the operands present in the expression are true otherwise it will give the result as false if either one of them is false or both of them are false.In the question it states that the expression in true either or both of it's operand are true.

Hence the answer is true.

4 0
2 years ago
Suppose your company has decided that it needs to make certain busy servers faster. Processes in the workload spend 60% of their
vekshin1

Answer:

CPU need 50% much faster

disk need 100% much faster

Explanation:

given data

workload spend time CPU  = 60%

workload spend time I/O = 40%

achieve overall system speedup = 25%

to find out

How much faster does CPU need and How much faster does the disk need

solution

we apply here Amdahl’s law for the overall speed of a computer that is express as

S = \frac{1}{(1-f)+ \frac{f}{k} }      .............................1

here f is fraction of work i.e 0.6 and S is overall speed  i.e 100% + 25% = 125 % and k is speed up of component

so put all value in equation 1 we get

S = \frac{1}{(1-f)+ \frac{f}{k} }  

1.25 = \frac{1}{(1-0.6)+ \frac{0.6}{k} }  

solve we get

k = 1.5

so we can say  CPU need 50% much faster

and

when f = 0.4 and S = 125 %

put the value in equation 1

S = \frac{1}{(1-f)+ \frac{f}{k} }  

1.25 = \frac{1}{(1-0.4)+ \frac{0.4}{k} }  

solve we get

k = 2

so here disk need 100% much faster

7 0
2 years ago
A signal travels from point A to point B. At point A, the signal power is 100 W. At point B, the power is 90 W. What is the atte
11Alexandr11 [23.1K]

Answer:

Attenuation = 0.458\ db

Explanation:

Given

Power at point A = 100W

Power at point B = 90W

Required

Determine the attenuation in decibels

Attenuation is calculated using the following formula

Attenuation = 10Log_{10}\frac{P_s}{P_d}

Where P_s = Power\ Input and P_d  = Power\ output

P_s = 100W

P_d = 90W

Substitute these values in the given formula

Attenuation = 10Log_{10}\frac{P_s}{P_d}

Attenuation = 10Log_{10}\frac{100}{90}

Attenuation = 10 * 0.04575749056

Attenuation = 0.4575749056

Attenuation = 0.458\ db <em>(Approximated)</em>

7 0
2 years ago
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