Answer:
See the components in explaination
Explanation:
In order to make it as IPv6, few key components should be supported, those components are given below:
The infrastructure must support the enhanced protocol StateLess Address Auto-Configuration (SLAAC).
Static addressing with DHCPv6, dynamic addressing with DHCPv6 and SLAAC are the methods used to configure the IPv6. The network administrator should able to understand and implement the IPv6 through the DHCPv6.
Other than the implementation, working of IPv4 and IPv6 are same. Therefore, the administrator need not to learn new information for its working.
As the IPv6 address length is 128-bit and purpose is for everything on line to have an IP address. It must allow the internet to expand faster devices to get internet access quickly.
The DHCPv6 is not supported by all windows. Therefore, network administrator should check the corresponding Operating system (OS) would support the DHCPv6 for IPv6.
The network administrator must have good knowledge and skills on the IPv6.
The above mentioned key components should be verified by the network administrator in order to support for IPv6 project with DHCPv6.
Answer:
In terms of efficient use of memory: Best-fit is the best (it still have a free memory space of 777KB and all process is completely assigned) followed by First-fit (which have free space of 777KB but available in smaller partition) and then worst-fit (which have free space of 1152KB but a process cannot be assigned). See the detail in the explanation section.
Explanation:
We have six free memory partition: 300KB (F1), 600KB (F2), 350KB (F3), 200KB (F4), 750KB (F5) and 125KB (F6) (in order).
Using First-fit
First-fit means you assign the first available memory that can fit a process to it.
- 115KB will fit into the first partition. So, F1 will have a remaining free space of 185KB (300 - 115).
- 500KB will fit into the second partition. So, F2 will have a remaining free space of 100KB (600 - 500)
- 358KB will fit into the fifth partition. So, F5 will have a remaining free space of 392KB (750 - 358)
- 200KB will fit into the third partition. So, F3 will have a remaining free space of 150KB (350 -200)
- 375KB will fit into the remaining partition of F5. So, F5 will a remaining free space of 17KB (392 - 375)
Using Best-fit
Best-fit means you assign the best memory available that can fit a process to the process.
- 115KB will best fit into the last partition (F6). So, F6 will now have a free remaining space of 10KB (125 - 115)
- 500KB will best fit into second partition. So, F2 will now have a free remaining space of 100KB (600 - 500)
- 358KB will best fit into the fifth partition. So, F5 will now have a free remaining space of 392KB (750 - 358)
- 200KB will best fit into the fourth partition and it will occupy the entire space with no remaining space (200 - 200 = 0)
- 375KB will best fit into the remaining space of the fifth partition. So, F5 will now have a free space of 17KB (392 - 375)
Using Worst-fit
Worst-fit means that you assign the largest available memory space to a process.
- 115KB will be fitted into the fifth partition. So, F5 will now have a free remaining space of 635KB (750 - 115)
- 500KB will be fitted also into the remaining space of the fifth partition. So, F5 will now have a free remaining space of 135KB (635 - 500)
- 358KB will be fitted into the second partition. So, F2 will now have a free remaining space of 242KB (600 - 358)
- 200KB will be fitted into the third partition. So, F3 will now have a free remaining space of 150KB (350 - 200)
- 375KB will not be assigned to any available memory space because none of the available space can contain the 375KB process.
Answer:
// program in C++ to check leap year.
// include header
#include<iostream>
using namespace std;
// main function
int main() {
// variable
int inp_year ;
// ask user to enter year
cout<<"Enter year:";
// read year
cin>>inp_year;
// check year is leap or not
if (((inp_year % 4 == 0) && (inp_year % 100 != 0)) || (inp_year % 400 == 0))
// if leap year , print leap year
cout<<inp_year<<" is a leap year.";
else
// print not leap year
cout<<inp_year<<" is not a leap year.";
return 0;
}
Explanation:
Read year from user.Then check if year is divisible by 4 and not divisible by 100 or year is divisible by 400 then year is leap year.otherwise year is not leap year.
Output:
Enter year:1712
1712 is a leap year.
Answer:
B. Fuser unit
Explanation:
Based on the scenario that is being described it can be said that the most likely problem is the Fuser unit. This is a part that plays an important role in the printing process. This unit melts the toner and compresses it in order to leave the impression on the paper with heat. A faulty fuser unit will not compress correctly and leave wet ink on the paper causing it to smear.
