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2 years ago

If there are 2.2 pounds in 1 kilogram how many pounds are there in x kilograms?

Mathematics

1 answer:

nirvana33 [79]2 years ago

5 0

Answer:

P=x/2.2

Step-by-step explanation:

We can create an equation to solve this.

Let the number of pounds be P

Let the number of kilograms be X

Now, we know that for 1 kilogram, there is 2.2 pounds.

Therefore if we have 1 kilogram (X) then we will have 2.2 pounds (P).

All you have to do now is rearrange the equation to find the number of pounds in x kilograms. To do this divide both sides by 2.

Therefore you will get P=x/2.2

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You are given rectangle ABCD on the grid shown and are told that the figure is to be dilated from the origin, but you are not to

Alenkinab [10]

Answer:

The new coordinates of point D(-4, -4) after the dilation by a scale factor of 1/2 will be: D'(-2, -2)

Step-by-step explanation:

The rectangle ABCD on the grid shown is attached below.

From the grid, it is clear that the coordinates of point D are (-4, -4)

i.e. D(-4, -4)

As we are told that the figure is to be dilated from the origin.

A dilation tends to stretch or shrink the original figure, depending upon scale factor.

If scale factor > 1, then the image gets enlarged

If the scale factor < 1, the image gets reduction

When we dilate a figure from the origin by any scale factor, the new coordinates of the image can be obtained by multiplying the scale factor with the coordinates of the original object/figure.

As the the coordinates of point D are (-4, -4). If we dilate the figure by a scale factor of 1/2, the new new coordinates of point D would be:

P(x, y) → P'(1/2x, 1/2y)

D(-4, -4) → D'(-4/2, -4/2) or D'(-2, -2)

Therefore, the new coordinates of point D(-4, -4) after the dilation by a scale factor of 1/2 will be: D'(-2, -2)

7 0

2 years ago

A botanist collected one leaf at random from each of 10 randomly selected mature maple trees of the same species. The mean and t

Zarrin [17]

Answer:

One sample t-test for population mean would be the most appropriate method.

Step-by-step explanation:

Following is the data which botanist collected and can use:

Sample mean
Sample Standard Deviation
Sample size (Which is 10)
Distribution is normal

We have to find the best approach to construct the confidence interval for one-sample population mean. Two tests are used for constructing the confidence interval for one-sample population mean. These are:

One-sample z test for population mean
One-sample t test for population mean

One sample z test is used when the distribution is normal and the population standard deviation is known to us. One sample t test is used when the distribution is normal, population standard deviation is unknown and sample standard deviation is known.

Considering the data botanist collected, One-sample t test would be the most appropriate method as we have all the required data for this test. Using any other test will result in flawed intervals and hence flawed conclusions.

Therefore, One-sample t-test for population mean would be the most appropriate method.

8 0

2 years ago

A particular brand of tires claims that its deluxe tire averages at least 50,000 miles before it needs to be replaced. From past

Volgvan

Answer: We reject the null hypothesis, and we use Normal distribution for the test.

Step-by-step explanation:

Since we have given that

We claim that

Null hypothesis : $H_0:\mu\geq 50000$

Alternate hypothesis : $H_1:\mu$

There is 5% level of significance.

$\bar{X}=46800\\\\\sigma=9800\\\\n=29$

So, the test statistic would be

$z=\dfrac{\bar{X}-\mu}{\dfrac{\sigma}{\sqrt{n}}}\\\\z=\dfrac{46800-50000}{\dfrac{9800}{\sqrt{29}}}\\\\z=-1.75$

Since alternate hypothesis is left tailed test.

So, p-value = P(z≤-2.31)=0.0401

And the P-value =0.0401 is less than the given level of significance i.e. 5% 0.05.

So, we reject the null hypothesis, and we use Normal distribution for the test.

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2 years ago

Logan wants to move to a new city. He gathered graphs of temperatures for two different cities. Which statements about the data

Bad White [126]

Answer:

The correct options are;

Therefore, City A is likely to have temperatures that remain fairly constant all year round because it has a compact interquartile range compared to that of City B

City B is likely to have more extreme temperatures with colder days in the winter and hotter days in the summer because the range is greater than that of A

Step-by-step explanation:

Here we have for City A

Maximum - Minimum = 10

Interquartile range =3

City B

Maximum - Minimum = 18.5

Interquartile range =9.5

Therefore, City A is likely to have temperatures that remain fairly constant all year round because it has a compact interquartile range compared to that of City B

City B is likely to have more extreme temperatures with colder days in the winter and hotter days in the summer because the range is greater than that of A.

7 0

2 years ago

Read 2 more answers

A simple random sample of 100 concert tickets was drawn from a normal population. The mean and standard deviation of the sample

alexandr402 [8]

Answer:

We accept the null hypothesis and the population mean is $120.

Step-by-step explanation:

We are given the following in the question:

Sample size, n = 100

Sample mean, $\bar{x}$ = $120