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shtirl [24]
2 years ago
15

jack wants to weigh at most 176 pounds before the baseball season begins. he has already lost 15 pounds. he belives he can lose

1.5 pounds a week.if jack weighed 197 pounds before his weight loss about loss about how many week will it take for jack to get to his desired weight
Mathematics
1 answer:
VikaD [51]2 years ago
6 0
The answer will be 4 weeks. You know the constant is 1.5 lbs per week and you will multiply that by however many weeks it takes to reach 176
197-(1.5x) would be your equation and since he’s already lost 15 pounds you will include that by subtracting 15 from the equation as well 197-(1.5(4))=191
191-15=176
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What is the measurement of N?<br><br>A) 23° <br><br>B) 45° <br><br>C) 73° <br><br>D) 81°
alina1380 [7]

D) 81°

explanation:

90°-9° =81°

5 0
2 years ago
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Mr. Malloy wants to make sure Amo and Javier get the best possible grade after five tests and can either give a grade based on t
joja [24]
The data has been properly arranged in tabular form and is shown below in the image.

First we need to find the mean and median of scores of both students.

1) For Amo:
Mean = \frac{97+92+89+55+90}{5}=84.6
Median = Middle Value when data is arranged in ascending order = 90

2) For Javier:
Mean =\frac{68+97+65+92+95}{5}=83.4
Median = Middle Value when data is arranged in ascending order = 92

For both the students, value of Median is larger then the mean. So in order to give the best possible grade Mr. Malloy should use the median score for both students.

8 0
2 years ago
Read 2 more answers
-6(2r +8)=-10(r-3)<br> I need the work to
barxatty [35]

Answer:

r = -39

Step-by-step explanation:

So we are trying to solve the equation for r.

-6(2r + 8) = -10(r - 3)

Divide both sides by -2. (This will make distributing much easier.)

3(2r + 8) = 5(r - 3)

Distribute the 3 on the left side and the 5 on the right side,

6r + 24 = 5r - 15

Subtract 24 from both sides.

6r = 5r - 39

Subtract 5r from both sides.

r = -39

So now we have solve the equation.

I hope you find my answer and explanation to be helpful. Happy studying. :)

5 0
2 years ago
From Statistics and Data Analysis from Elementary to Intermediate by Tamhane and Dunlop, pg 265. A thermostat used in an electri
Leviafan [203]

Answer:

t=\frac{201.77-200}{\frac{2.41}{\sqrt{10}}}=2.32    

The degrees of freedom are given by:

df=n-1=10-1=9  

The p value for this case is given by:

p_v =2*P(t_{(9)}>2.32)=0.0455    

For this case since the p value is lower than the significance level we have enough evidence to reject the null hypothesis and we can conclude that the true mean is significantly different from 200 F.

Step-by-step explanation:

Information given

data: 202.2 203.4 200.5 202.5 206.3 198.0 203.7 200.8 201.3 199.0

We can calculate the sample mean and deviation with the following formulas:

\bar X= \frac{\sum_{i=1}^n X_i}{n}

\sigma=\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}

\bar X=201.77 represent the sample mean    

s=2.41 represent the sample standard deviation    

n=10 sample size    

\mu_o =200 represent the value that we want to test    

\alpha=0.05 represent the significance level for the hypothesis test.    

t would represent the statistic

p_v represent the p value for the test

Hypothesis to test

We want to determine if the true mean is equal to 200, the system of hypothesis are :    

Null hypothesis:\mu = 200    

Alternative hypothesis:\mu = 200    

The statistic for this case is given by:

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}} (1)    

The statistic is given by:

t=\frac{201.77-200}{\frac{2.41}{\sqrt{10}}}=2.32    

The degrees of freedom are given by:

df=n-1=10-1=9  

The p value for this case is given by:

p_v =2*P(t_{(9)}>2.32)=0.0455    

For this case since the p value is lower than the significance level we have enough evidence to reject the null hypothesis and we can conclude that the true mean is significantly different from 200 F.

4 0
2 years ago
Jonah was standing at an elevation somewhere between Negative 1 and one-half and Negative 2 and one-third meters with regards to
Agata [3.3K]

Options :

A number line going from negative 3 to positive 3 in increments of 1.

1 and StartFraction 5 Over 6 EndFraction meters

Negative 2 and StartFraction 3 Over 6 EndFraction meters

2 and StartFraction 3 Over 6 EndFraction meters

Negative 1 and StartFraction 5 Over 6 EndFraction meters

Answer:

Negative 1 and StartFraction 5 Over 6 EndFraction meters

Step-by-step explanation:

Jonah's position range :

Between - 1 1/2 meters and - 2 1/3 meters with respect to sea level

With regards to sea level and the range of position given ; Jonah's position will be below sea level, that is Jonah's position cannot be a positive location on the number line, thus all options with positive values are incorrect.

Hence Jonah's position will be any number on a number line located in between :

-2 1/3 and - 1 1/2

That is

-2 1/3 ≤ Jonah's location ≤ - 1 1/2

-2 1/2 ( this is less than - 2 1/3) (incorrect)

-1 5/6 lies in between the given range and is thus a possible position.

7 0
2 years ago
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