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kvasek [131]
2 years ago
4

A restaurant sells pizzas for which you can choose from nine toppings.

Mathematics
1 answer:
olchik [2.2K]2 years ago
7 0

Answer:

A) 362880

B) 4

Step-by-step explanation:

Given that a customer can choose from nine toppings

To find different types of pizza the restaurant serve, we will permutate it. That is 9 factorial

9! = 362880 different types of pizza

B) if it wishes to offer at least 2,000 different types of pizza, then,

9 permutation x is equal to 2000. That is 9Px = 2000

Let's find x

9!/(9-x)! = 2000

(9 - x)! = 9!/2000

(9-x)! = 181.44

Let assume x = 4

(9 - 4)! = 181.44

5! = 181.44

120 = 181.44

The two numbers are very close. Therefore, 4 is the minimum number of toppings the restaurant must provide if it wishes to offer at least 2,000 different types of pizza?

toppings

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