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ikadub [295]
2 years ago
6

A local regulator has calculated the average cost of production for the public water utility. Theregulator has allowed an adjust

ment for the normal rate of profit the firm should expect to earn, and then set the price that consumers can be charged accordingly. In this instance, the regulator has used which of the following?
A. cost-plus regulation
B. cost-plus analysis
C. price-cap regulation
D. market-price analysis
Business
1 answer:
Varvara68 [4.7K]2 years ago
8 0

Answer:

A. cost-plus regulation

Explanation:

When a local regulator calculates the average cost of production for the public water utility or any other service and allow an adjustment for the normal rate of profit the firm should expect to earn, and then set the price that consumers can be charged accordingly, this is known as cost-plus regulation.

It is usually carried out by the government.

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Determining the Optimal Product Mix with One Constrained Resource Relax Spas provides two types of massage services, the Full Bo
m_a_m_a [10]

Answer:

Full body = $132

For trouble spots = $180

Explanation:

The computation of contribution margin per hour is shown below:-

For Full body

Contribution per service = $198

Massage time required in minutes = $90

Massage time required (90 min ÷ 60 min) = $1.5

Contribution per hour = $198 × $1.5

= $132

For Trouble spots

Contribution per service = $90

Massage time required in minutes = $30

Massage time required (30 min ÷ 60 min) = $0.5

Contribution per hour = $90 × $0.5

= $180

5 0
2 years ago
A car dealer who sells only late-model luxury cars recently hired a new salesman and believes that this salesman is selling at l
Natasha2012 [34]

Answer:

t=\frac{5000-5600}{\frac{800}{\sqrt{16}}}=-3      

Explanation:

Data given and notation      

\bar X=5000 represent the sample mean      

s=800 represent the standard deviation for the sample      

n=16 sample size      

\mu_o =5600 represent the value that we want to test    

\alpha represent the significance level for the hypothesis test.    

t would represent the statistic (variable of interest)      

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.      

We need to conduct a hypothesis in order to determine if the mean is lower than 5600, the system of hypothesis would be:      

Null hypothesis:\mu \geq 5600      

Alternative hypothesis:\mu < 5600      

We don't know the population deviation, so for this case is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:      

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}} (1)      

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic      

We can replace in formula (1) the info given like this:      

t=\frac{5000-5600}{\frac{800}{\sqrt{16}}}=-3      

4 0
2 years ago
Consider a risky portfolio. The end-of-year cash flow derived from the portfolio will be either $70,000 or $200,000 with equal p
xenn [34]

Answer:

A) 964,286

B) 14

C) 750,000

Explanation:

The portfolios expected return = (0.5 x $70,000) + (0.5 x $200,000) = $35,000 + $100,000 = $135,000

If the risk free investment yields 6% per year, and you require a risk premium of 8%, then the total interest rate that the portfolio yields must be 6% + 8% = 14%

you will be willing to pay: $135,000 / 14% = $964,286 for the portfolio

if the risk premium increase by 4%, then the price of the portfolio will decrease to: $135,000 / 18% = $750,000

4 0
2 years ago
A regional automobile dealership sent out fliers to prospective customers indicating that they had already won one of three diff
Bas_tet [7]

Answer:

the requirements are missing, so I looked for a similar question.

<em>a. How many fliers do you think the automobile dealership sent​ out? </em>

<em> b. Using your answer to​ (a) and the probabilities listed on the​ flier, what is the expected value of the prize won by a prospective customer receiving a​ flier? </em>

<em> c. Using your answer to​ (a) and the probabilities listed on the​ flier, what is the standard deviation of the value of the prize won by a prospective customer receiving a​ flier?</em>

a) the total fliers sent out = 31,246 + 1 + 1 = 31,248

b) expected value = [(1 x $28,000) + (1 x $100) + (31,246 x $5)] / 31,248 = $5.90

c) σ² = [($28,000 - $5.90)² x 1] + [($100 - $5.90)² x 1] + [($5 - $5.90)² x 31,246] / 31,248 = ($783,669,634.80 + $8,854.81 + $25,309.26) / 31,248 = $25,080.13

σ = √$25,080.13 = $158.37

4 0
2 years ago
Johnson is an executive vice president at Conecom Hardware. He researches a proposal by a larger company, Openlane Hardware, to
WARRIOR [948]

Answer: Turn down the acquisition offer and prepare to resist a hostile takeover.

Explanation:

Since Johnson analysed the past performance of Openlane hardware and found out that past performance, conducting focus groups, and interviewing Openlane employees, Johnson concludes that the company has poor profit margins, sells shoddy merchandise, and treats customers poorly, then Johnson and Conecom Hardware should turn down the acquisition offer and prepare to resist a hostile takeover.

In this case, the merge between the companies will have a negative impact on Johnson and Conecom hardware due to the fact that the company has a bad reputation already and this can have an effect on Conecom. Therefore, the acquisition offer should be turned down.

5 0
2 years ago
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