Movement of mouth and lips
Answer:
Valine-Leucine-Proline-Lysine-Histidine
Explanation:
The central dogma of biology is the process by which DNA is used to synthesize RNA and subsequently amino acid sequence (PROTEIN). The processes of transcription and translation is used in gene expression. Transcription is the process whereby the information encoded in a DNA molecule is used to synthesize a mRNA molecule. Transcription is catalyzed by RNA polymerase enzyme, which uses complementary base pairing rule i.e Adenine(A)-Thymine(T), Guanine(G)-Cytosine(C) pairing.
N.B: Thymine is replaced by Uracil in the mRNA
For the above DNA sequence: CAC GAC GGA TTC GTA, the mRNA sequence will be: GUG CUG CCU AAG CAU
Translation is the second process of gene expression which involves the synthesis of an amino acid sequence from an mRNA molecule. The mRNA is read in a group of three nucleotides called CODON. Each codon specifies an amino acid (see attached image for genetic code)
Based on the attached genetic code, an mRNA sequence: GUG CUG CCU AAG CAU will encode an amino acid sequence: Valine(Val) - Leucine (Leu) -Proline (Pro) -Lysine (Lys) - Histidine (His).
GUG specifies Valine amino acid
CUG specifies Leucine amino acid
CCU specifies Proline amino acid
AAG specifies Lysine amino acid
CAU specifies Histidine amino acid
No solo seria natural porque son differentes y asy creses pero solo si isiste todo igual
The role of a Detrivore is to help recycle the nutrients in the soil. They break down complex proteins, and other materials so the answer is A. to decompose dead animals.
1. Cellular respiration is a metabolic pathway that occurs inside the cell. During cellular respiration, glucose molecule is broken down in the presence of oxygen.
2. During cellular respiration, ATP (Adenosine Triphosphate) molecule is also produced that acts as energy currency and directly powers cell work.
3. Amylase is an enzyme that helps in digestion. It catalyzes the hydrolysis of starch into simple sugars. If amylase is present in normal amount it will break down starch into disaccharides. If the amount of disaccharidase amount is less than usual then less disaccharides will be broken down into monosaccharides. Thus the production of monosaccharides will decrease.
4. In the reactions shown above, the end product is largely dependent on the last enzyme. If Enzyme3 is in less amount than usual then there will be greatest reduction in the production of G and H. This is because the formation of product in any reaction is dependent on the substrate concentration and enzyme concentration.