Answer:
Multiple RODS send combined messages to a bipolar cell, whereas a single _CONE may link directly to a single bipolar cell.
Explanation:
The rods and cone cell are photoreceptive cells in the eye. The Rod cells are sensitive to coloured lights stimulus, while the Cones cells are sensitive to black and white stimulus.
Answer:
Option 4
Explanation:
Folate is vitamin B and occurs naturally in various food items such as green leafy vegetable, lentils, peas, beans, in fruits such as banana, melon, and enriched products such as bread, juices etc. Folate is essential for making up genetic material or DNA. Out of all given options, option 4 has both lentil and spinach (green leaves) which are rich source of folate. Option 1 has bread as a source of folate. Hence, the correct answer is option 4.
Answer:
It doesn't name the phases of mitosis, but leads us to believe they are shown.
Answer:
A serial dilution and the following plating experiment is done in order to determine the actual amount of bacteria/microbes in a specific volume of soil sample. As a standard test, a set volume of the lower dilution is obtained and positioned on a median plate and permitted to increase for the needed amount of time. The amount of colonies is evaluated and thus the overall Colony Forming Units (CFU) is determined by unit volume of the sample plated and therefore the volume of soil sample employed.
Therefore,
The calculation is done using:
CFU/ml = Number of colonies appeared × dilution factor / volume plated
Given,
Number of colonies appeared = 97
dilution factor = 10^(-6)
volume plated = 1/10 = 0.1
This will help us calculate it as:
CFU/ml = 97 * 10^(-6) / 0.1
= 97 * 10^(-7) CFU/ml
This CFU/ml helps determine the amount of bacterial colonies per unit volume of sample plated.
Given,
The original sample as 1g or 1000 mg of soil in its total volume.
Therefore,
The number of bacteria can be calculated using:
Amount of bacteria in original sample
= 97 * 10^(-7) CFU/ml × 1/ 1000 mg
= 9.7 * 10^(-3) CFU/mg
Either C or D. I think C, but I'm not too sure...
