The inferior angle of the scapula is the bony projection that occurs bilaterally on the posterior aspect at the mid-thorax.
The inferior angle of the scapula is formed by the unification of the medial and lateral borders of the scapula. It is thick and rough and its posterior or dorsal part serves as an attachment to the Teres major muscle, to which the latissimus dorsi glides over.
Answer:
99% water, sodium chloride, trace amounts of wastes, and vitamin C
Explanation:
Eccrine glands are the main and major sweat glands of our body. These glands are found all over the skin but their density is higher on palm, soles, and head.
99% of the secretion of the eccrine gland is water and in rest 1% it contains sodium, trace amounts of waste and a high amount of vitamin C is lost by the eccrine gland.
As the eccrine gland is responsible for sweating so it helps in thermoregulation in the body. As 99% of secretion is water therefore dehydration and water loss is the major worry during excessive sweating.
<span>In order to find the value of "a" and "b", first of all perform the multiplication in the parenthesis.
Thus
(3.5x1016) = 3556
and
(2.2x1010) = 2222
As per question;
(3556)x(2222) = 10 axb
By dividing both sides by "10"
we get
(3556)x(222.2) = axb
or
(355.6)x(2222) = axb
by comparing both sides of the equation,
we get that a = 3556 and b = 222.2
or
a = 355.6 and b = 2222
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The plasma membrane of axon is called axolemma. The potassium and sodium leak channels leak the sodium and potassium ions inside the cell respectively. The leak channels provide the constant movement of ions across the membrane. Potassium and sodium ions are positively charged, thus entry of positively charged ions inside the cell makes the cell more positively charged than the environment outside the cell. The environment outside the cell becomes more negatively charged. This leads in the negative membrane potential of axolemma.
Answer:
Placing salty water in A and distilled water in B.
Explanation:
The fastest net rate of water movement into the A-side will occur if we place salty water on that side and distilled water in the other one. The reason for this is that the A-side contains a higher concentration of solute than B. So, the water will pass the semipermeable membrane and go to the A-side to valance the concentrations on both sides. As we can see, there is an increase in the net rate of water movement into A.
