Solution :
In Gizmo experiment, when both the intensity of light and carbon dioxide level is high, the rate of photosynthesis will maximize.
A). If the temperature is too hot or cold, it becomes difficult to find the ideal intensity of light because if the temperature is hot, the light intensity will be too high and thus the chlorophyll will get damaged. While if it too low, then it will be difficult for the proper functioning of the cells. And hence the photosynthesis will not take place.
B). It will be considered as a limiting factor if the light intensity is low. With light intensity being low, it will be difficult for the plant for survival and ideal carbon dioxide level will have no role. This amount of carbon dioxide does not help the plant to survive as the light intensity is now a rate limiting factor.
Answer:
The factors which remained constant are as follows -
- material used as the membrane
- amount of substances used
- number of trials
The factors which have shown variation are as follows -
- molecule size (large starch molecules vs. small glucose molecules)
- whether the molecules diffused through the membrane (tubing)
Explanation
Some factors with in the experiments remained constant from the point of starting of the experiment to its end. While some factors were varied to study its impact on the experiment rate of progression or on the final product formed. Thus , out of the following given factors, the ones that remained constant are -
- material used as the membrane
- amount of substances used
- number of trials
The factors which have shown variation are as follows -
- molecule size (large starch molecules vs. small glucose molecules)
- whether the molecules diffused through the membrane (tubing)
Answer: Option B
Explanation: First we should understand the role of enzyme and acid here. Pepsin is an enzyme which will break down proteins into simple monomers (like amino acids). And, acid causes digestion which means it will break down the protein into its respective elements and compounds. Water will act as a control in this experiment.
Option B is correct because it has all three criteria- 1. Control [water + protein] 2. With enzyme [egg white + pepsin] 3. With acid and enzyme
So this will give us an idea whether pepsin alone is breaking down the protein or digesting it. And there would be difference in test tube B and C. So this will clear the difference.
Option A is incorrect because it has not mentioned any different test tube for checking what happened with the protein. And, Option C is incorrect because mass of egg white will remain same after digestion also.
Question 2 is ansethosphere
Question 3 is high pressure(i think)
