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2 years ago

Explain why a polar curve is not always bounded

Mathematics

2 answers:

GalinKa [24]2 years ago

8 0

Answer:

vvvvvvvvvv

Step-by-step explanation:

there are lots of common polar curves that are bounded therefore a polar curve is not always bounded all the time. a polar curve is required to have an unbounded function (right side of r = f(θ)) to be an unbounded polar.

nikitadnepr [17]2 years ago

8 0

Answer:

There are lots of common polar curves that are bounded therefore a polar curve is not always bounded all the time. A polar curve is required to have an unbounded function (right side of r = f(θ)) to be an unbounded polar.

be safe and have a day

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Parallelogram ABCD is rotated to create image A'B'C'D'. On a coordinate plane, 2 parallelograms are shown. The first parallelogr

Gala2k [10]

Answer:

(x,y)→(y,-x)

Step-by-step explanation:

Parallelogram ABCD:

A(2,5)

B(5,4)

C(5,2)

D(2,3)

Parallelogram A'B'C'D':

A'(5,-4)

B'(4,-5)

C'(2,-5)

D'(3,-2)

Rule:

A(2,5)→A'(5,-2)

B(5,4)→B'(4,-5)

C(5,2)→C'(2,-5)

D(2,3)→D'(3,-2)

so the rule is

(x,y)→(y,-x)

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2 years ago

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Jorge and Jillian have cell phones with different service providers. Jorge pays $50 a text month and $1 per text message sent. J

barxatty [35]

Answer:

When they send 25 texts each, their bills will be equal

Step-by-step explanation:

Let the number of text messages that makes their bill equal be x

Jorge will have a bill of = 50 + x(1) = 50 + x

Jillian will have a bill of = 72 + 0.12(x) = 72 + 0.12x

Since their bills will now be equal, we equate both

50 + x = 72 + 0.12x

72-50 = x-0.12x

22 = 0.88x

x = 22/0.88

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2 years ago

1. There are 125 juniors at the high school.How many ways can they elect a

valentinak56 [21]

Answer: 1. 1,906,500

2. 840

Step-by-step explanation:

1. Given: There are 125 juniors at the high school.

Total positions = 3 [president,vice president, and secretary]

Then, Number of ways to elect a president,vice president, and secretary( which is in order) out of 125 juniors = $^{125}P_{3}=\dfrac{125!}{(125-3)!}$ [Using permutations]

$=\dfrac{125!}{122!}\\\\=\dfrac{125\times124\times123\times122!!}{122!}\\\\=125\times124\times123\\\\=1906500$

Hence, Required ways =1906500

(2) Given word : "RHOMBUS"

Total letters= 7

By permutation, the umber of 4-letter arrangements = $^7P_4=\dfrac{7!}{(7-4)!}=\dfrac{7!}{3!}$

$=\dfrac{7\times6\times5\times4\times3!}{3!}\\\\= 7\times6\times5\times4\\\\=840$

Hence, required ways = 840

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2 years ago

A treasure map says that a treasure is buried so that it partitions the distance between a rock and a tree in a 5:9 ratio. Marin

djyliett [7]

Answer:

A) (7.6, 8.8)

which are the coordinates of the treasure.

Missing Problem Statement:

Given Options:

A) (11.4, 14.2)

B) (7.6, 8.8)

C) (5.7, 7.5)

D) (10.2, 12.6)

I have added the picture showing the traced map onto a coordinate plane to find exact location of treasure.

The coordinates of Tree are (16,21)

Coordinates of rock are (3,2)

Step-by-step explanation:

Let,

Coordinates of treasure be (a,b)

$d_{1}$ = distance from tree to treasure

$d_{2}$ =distance from rock to treasure

$d_{1}=\sqrt{(16-x)^2 + (21-y)^2}$

$d_{2}=\sqrt{x\2 + (y-2)^2}$

Given ratio between rock and tree, $\frac{d_{2}}{ d_{1}}=\frac{5}{9}$ = 0.55_______(Equation.1)

which will be used to locate the treasure.

Now we just need to cross check by putting the coordinates given in the options one by one to find out value of $d_{1}$ , $d_{2}$ and checking if it satisfies the Equation 1.

Check (A) (11.4, 14.2)

$d_{2}$ = 14.8, $d_{1}$ = 8.2,

$\frac{d_{2}}{ d_{1}}$ = 1.8

Check (C) (5.7, 7.5)

$d_{2}$ = 6.13, $d_{1}$ = 16.98,

$\frac{d_{2}}{ d_{1}}$ = 0.36

Check (D) (10.2, 12.6)

$d_{2}$ = 12.8, $d_{1}$ = 10.2,

$\frac{d_{2}}{ d_{1}}$ = 1.25

Check (B) (7.6, 8.8)

$d_{2}$ = 8.2, $d_{1}$ = 14.8,

$\frac{d_{2}}{ d_{1}}$ = 0.55

Which satisfies Equation 1, such that ratio between rock and tree is 5:9 or $\frac{d_{2}}{ d_{1}}=\frac{5}{9}$ = 0.55

So, the coordinates of the treasure are (B) (7.6, 8.8)

7 0

2 years ago

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Suppose we want to choose 2 objects, without replacement, from the 5 objects pencil, eraser, desk, chair, and lamp. (a)How many

BigorU [14]

Answer:

a) 20 ways

b) 10 ways

Step-by-step explanation:

When the order of selection/choice matters, we use Permutations to find the number of ways and if the order of selection/choice does not matter, we use Combinations to find the number of ways.

Part a)

We have to chose 2 objects from a group of 5 objects and order of choice matters. This is a problem of permutations, so we have to find 5P2

General formula of permutations of n objects taken r at time is:

$nPr=\frac{n!}{(n-r)!}$

Using the value of n=5 and r=2, we get:

$5P2=\frac{5!}{(5-2)!} =20$

Therefore, we can choose 2 objects from a group of 5 given objects if the order of choice matters.

Part b)

Order of choice does not matter in this case, so we will use combinations to find the number of ways of choosing 2 objects from a group of 5 objects which is represented by 5C2.

The general formula of combinations of n objects taken r at a time is:

$nCr=\frac{n!}{r!(n-r)!}$

Using the value of n=5 and r=2, we get:

$5C2=\frac{5!}{2!(5-2)!} =10$

Therefore, we can choose 2 objects from a group of 5 given objects if the order of choice does not matters.

3 0

2 years ago

Read 2 more answers