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serious [3.7K]
2 years ago
9

Write a function shampoo_instructions() with parameter num_cycles. If num_cycles is less than 1, print "Too few.". If more than

4, print "Too many.". Else, print "N : Lather and rinse." num_cycles times, where N is the cycle number, followed by "Done.". Sample output with input: 2 1 : Lather and rinse. 2 : Lather and rinse. Done. Hint: Define and use a loop variable.
Computers and Technology
1 answer:
Masteriza [31]2 years ago
7 0

Answer:

See explaination

Explanation:

#Run the code in the python version 3.x.

#Define the function.

def shampoo_instructions(num_cycles):

#Check the cycles to be greater than 1.

if num_cycles < 1:

#Display the statement.

print('Too few.')

#Check the cycles to be greater than 4.

elif num_cycles > 4:

#Display the statement.

print('Too many.')

#The else part.

else:

#Initialize the variable.

N = 1;

#Begin the for loop.

for N in range(N, num_cycles+1):

#Print the result.

print(N , ": Lather and rinse.")

#Print the statement.

print('Done.')

#Call the function.

shampoo_instructions(2)

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Answer:

// program in C++ to check leap year.

// include header

#include<iostream>

using namespace std;

// main function

int main() {

// variable

  int inp_year ;

  // ask user to enter year

  cout<<"Enter year:";

  // read year

  cin>>inp_year;

  // check year is leap or not

  if (((inp_year % 4 == 0) && (inp_year % 100 != 0)) || (inp_year % 400 == 0))

  // if leap year , print leap year

     cout<<inp_year<<" is a leap year.";

  else

  // print not leap year

     cout<<inp_year<<" is not a leap year.";

  return 0;

}

Explanation:

Read year from user.Then check if year is divisible by 4 and not divisible by 100 or year is divisible by 400 then year is leap year.otherwise year is not  leap year.

Output:

Enter year:1712                                                                                                            

1712 is a leap year.

6 0
2 years ago
Read 2 more answers
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Answer:

false

Explanation:

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2 years ago
A large software development company employs 100 computer programmers. Of them, 45 areproficient in Java, 30 in C, 20 in Python,
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Answer:

18, 13, 19

Explanation:

Number of computer programmers proficient only in Java = 45 - ( 1+1+6) = 37

Number of computer programmers proficient only in C++ = 30 - (6+1+5) = 18

Number of computer programmers proficient only in python = 20 - ( 1+1+5) = 13

Number of computer programmers are not proficient in any of these three languages = 100 - ( 37 + 18 + 13 + 1+ 1+ 5+ 6 ) = 100 - 81 = 19

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Answer:

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Risks

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1. Risks

a. employees  

              a. physical illness

              b. mental illness

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2. Customers  

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3.  Benefits

However, the content seems to be complete now, and hence not anything else is required. And since its not something very tough to decide to go with, bite the bullet is certainly not an issue.  

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Answer:

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Explanation:

3 0
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