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nalin [4]
2 years ago
4

Bryophyllum daigremontianum ("mother of thousands") produces hundreds of asexual baby plantlets that are genetically identical t

o the parent plant and can grow into mature plants. Predict whether plantlets obtained from a single parent plant but grown under different environmental conditions would likely show the same phenotypes.
O Although the plantlets start out genetically identical, different mutations in the different plantlets would result in different phenotypes under different environmental conditions.
O Even though the plantlets are genetically identical, they would likely show different phenotypes because of phenotypic plasticity.
O The offspring are all genetically identical, so they would likely show almost the same phenotypes under different environmental conditions.
O Since the plantlets are all genetically identical, they will only survive under the same environmental conditions as the parent, so the ones that survive will have the same phenotype as the parent.
Biology
1 answer:
user100 [1]2 years ago
6 0

Answer:

Even though the plantlets are genetically identical, they would likely show different phenotypes because of phenotypic plasticity.  

Explanation:

Phenotypic plasticity represents an adaptive mechanism and also an important feature of asexual organisms because it enables one genotype to produce different phenotypes in response to different environmental conditions

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The transport of molecules of a particular solute from inside an animal cell across the cell membrane to the extracellular fluid
Leona [35]

Answer:

the concentration of the solute is lower inside the cell than outside it

Explanation:

This question depicts the process of ACTIVE TRANSPORT, which is the movement of a substance against concentration gradient, hence, requires energy input (ATP) to occur. In this case, transporting a solute from inside an animal cell to the extracellular fluid across the cell membrane always requires energy.

This is because the concentration of solute inside the cell is much lower than that of the extracellular fluid, hence, to move the solutes against this concentration gradient (low to high), energy in form of ATP is required.

6 0
2 years ago
Transposons need to __________________ in order to limit their negative impact on the genome of the host cell. A. control their
nalin [4]

Answer:

The correct answer is B

Explanation:

Transposons need to regulate their copy number to avoid errors with chromosomal pairing during meiosis and mitosis such as unequal crossover.

A typical example of this error is called the Alu Sequence or Elements. Alu elements contain more than one million copies found everywhere in the genome of human beings.

Many inherited human diseases such as cancer are related to Alu insertions.

Cheers!

8 0
2 years ago
The plasma membrane forms a barrier which is ___________ on the outer and inner surface and _____________ on the interior
Elodia [21]

Answer:

The plasma membrane forms a barrier which is phospholipid bilayer on the outer and inner surface and compartments on the inferior  

5 0
2 years ago
Transport of D- and L- glucose proceeds at the same rate down an electrochemical gradietn by which ofhte following processes?
san4es73 [151]

Answer:

Explanation:

Active transport is the movement of molecules or substance from a region of lower concentration to a region of higher concentration across a cell membrane against the concentration gradient.

Active transport requires cellular energy and are of two types:

primary active transport that uses adenosine triphosphate (ATP), and secondary active transport that uses an electrochemical gradient.

Active transport helps in the uptake of glucose in the intestines.

Cotransport or secondary active transport is the movement of molecules across a membrane it uses electrochemical potential difference that is created by pumping ions in or out of the cell.

Cotransport helps in the transport of glucose across the cell membrane.

5 0
2 years ago
A student placed a semipermeable membrane inside a U-shaped channel with two chambers, as shown. The
yanalaym [24]

Answer:

Placing salty water in  A and distilled water in  B.

Explanation:

The fastest net rate of water movement into the A-side will occur if we place salty water on that side and distilled water in the other one. The reason for this is that the A-side contains a higher concentration of solute than B. So, the water will pass the semipermeable membrane and go to the A-side to valance the concentrations on both sides. As we can see, there is an increase in the net rate of water movement into A.

5 0
2 years ago
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