Answer:
The answer is XX.
Explanation:
Let us say that X is the dominant gene and x is the recessive gene for the height of the pea plants. Pea plants need to be homozygous or heterozygous to have the short phenotype which means it needs to have the genotype xx or Xx.
The F2 offspring has a ratio of 74,5% tall plants and 25,5% short plants. For these results, the stem height pea plant needs to be homozygous which is an XX genotype for the tall pea plant.
I hope this answer helps.
I think the correct answer would be the third option. Organisms that help break down dead organic material so it can be recycled into a usable form for other organisms are called decomposers and this would include some of the bacteria. Also, there is a number of bacteria that are capable of breaking down some of the harmful products like in recent studies there are bacteria that could dechlorinate the toxic PCB substance. Some bacteria, as well, lives in the human intestines which aids in the breaking down of the food into useful molecules. The third option is partially true since there are some bacteria like the cyanobacteria which produces oxygen but it does not contribute largely to the oxygen present in the atmosphere.
The genome of a goldfish contains 96 chromosomes. how many chromosomes will each daughter cell have after mitosis of a goldfish cell is complete
C. 95
Answer:
A. Calcium would be transported to the sarcoplasmic reticulum therefore contractions would cease.
Explanation:
A muscle fibre will stop contraction immediately ATP is used up. Also, muscle contraction will end as soon as the information from the motor neuron stops. This repolarizes the sarcolemma and T-tubules, thereby closing the voltage-gated calcium channels in the sarcoplasmic reticulum. Calcium ions are then pumped back into the sarcoplasmic reticulum, in order for tropomyosin to cover the binding sites on the actin strands again.
Answer:
Explanation:Twenty fruit flies are placed in each of four glass tubes. The tubes are sealed. Tubes I and II are partially covered with black paper; Tubes III and IV are not covered. The tubes are placed as shown. Then they are exposed to blue light for five minutes. The number of flies in the uncovered part of each tube is shown in the drawing.
These data show that these flies respond to (respond means move to or away from):
