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stepladder [879]
2 years ago
10

Scientists studying transcription in yeast (Saccharomyces cerevisiae) created an experimental strain that produced a modified RN

A polymerase containing a single amino acid substitution. The scientists determined the maximum elongation rate during transcription with and without the modified RNA polymerase enzyme (Figure 1 ).
The compound amanitin, which is commonly found in toxic mushrooms, is a specific RNA polymerase inhibitor. Amanitin binds to the RNA polymerase active site and inhibits transcription. In a second experiment, the scientists treated the wild-type and experimental strains of S. cerevisiae with a 40 μg/mL solution of amanitin and recorded the maximum elongation rate of the mRNA (Figure 2 ). Error bars represent ±2SEx¯ .


Identify the dependent variable in the experiments. Identify a control group missing from the second experiment. Justify the need for this control group in the second experiment.
Biology
1 answer:
SpyIntel [72]2 years ago
6 0

Answer:

elongation rate of strain of S.cerevisiae during transcription.

wild-type and experimental strain not treated with soultion of amanitin will be the control group. The elongation rate of mRNA of this group must be observed.

Explanation:

Dependent variable is one whose value depends on another value. Here effect of presence of mRNA polymerase enzyme and inhibtor on elnogatino rate of mRNA is being observed. So elongation rate is the dependent variable

Control group is one where independent variable whose effect is being observed can't influence the results. In experiment 2, the effect of inhibitor is being observed. So the control group must not have that inhibitor. Other conditions must remain same for experimentan and control group.

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A Xw+m+Xwm female was mated to a XwmY male. Out of 1000 total F1 progeny there were 230 flies that were otherwise wild type with
deff fn [24]
In order to calculate the distance between two alleles/genes that are found in the same chromosome, we need to know how often crossing-over happened (recombination frequency). We know from the text that white eyes were linked to miniature wings and that wild type eyes were linked to wild type wings, so any phenotype that's contrary to these parent combinations are a result of crossing-over. We know then that 230 flies + 240 flies were a result of such recombination. To calculate the recombination frequency we only need to divide these flies (total of recombinant flies) by the total of flies in the offspring and turn it into percentage.
\frac{230+240}{1000}=0.47
0.47*100%=47%
47 map units is the distance between the genes <span>for eye color and wing length.</span>
7 0
2 years ago
With the endosymbiotic hypothesis in mind, what structure within modern-day chloroplasts is likely derived from the cytoplasm of
Liono4ka [1.6K]

The chloroplasts had inner membrane

Explanation:

The primitive photoautotrophs utilized hydrogen sulphide as the electron donor to perform photosynthesis for energy production.  

Later upon understanding the endosymbiotic relationship of cyanobacteria which resided in the mitochondria of a eukaryotic host cell, the use of chloroplasts for photosynthesis was understood.  

Generations after generations led to the development of chloroplasts by the cyanobacteria due to this symbiotic relationships which developed into the chloroplasts.

The unique presence of the inner membrane and its components like the stroma, thyllakoids helped the organism to utilize water as the electron donor for photosynthesis like the present day eukaryotes. This is the main reason why cyanobacteria is considered as the ancestor for eukaryotes.

8 0
2 years ago
A boy threw a small bundle toward his girlfriend on a balcony 10. meters above him. The bundle stopped rising in 1.5 seconds. Ho
Alisiya [41]

Hi!


We know that the boy must have thrown the bundle with some initial velocity 'v', and that the bundle stops after 1.5 seconds at a height 's' with a final velocity 'u' -which would be 0.

Our known values thus are:

Time (t) = 1.5 s

Final velocity (u) = 0 m/s

Gravitational acceleration (g) = -9.8 m/s^(2)

<em>Note: that the acceleration is negative as it is opposing the direction of motion (acting  down on the object, causing deceleration)</em>

We will be using <em>equations of motion for an accelerating object</em> to solve first for initial velocity, in order to find the distance.

<h3>Initial Velocity using     <u>v = u + at</u></h3>

Rearranging the equation, and using the value 'g' as our acceleration, we get,<em> u = v - at</em>

u = 0 - (-9.8)(1.5) = 14.7m/s

<h3>Distance Travelled using   <u>v^2 = u^2 + 2as</u></h3>

Rearranging the equation, we get, <em>s= v^(2) - u^(2) / 2a</em>

s = 0^(2) - 14^(2) / 2(-9.8)                          

<em>Note: the negative sign is not a part of the initial velocity, but a part of the equation </em>

s = - 216.09 / -19.6 = 11.025 m


The distance traveled by the bundle is hence, ~ 11 meters, which is high enough for the girl to catch.


Hope this helps!


6 0
2 years ago
What will happen if the process of mitosis skipped telophase?
Papessa [141]
The nucleus would not split into two, therefore, they will not divide correctly
6 0
2 years ago
e erythrocyte (red blood cell) count increases after a while when an individual goes from a low to a high altitude because the _
Aloiza [94]

The answer is; concentration of oxygen and/or total atmospheric pressure is lower at high altitudes

This means that at high altitude, due to the low pressure, every breath has a lower oxygen content than at a lower altitude. This, therefore, necessitates the body to increase the erythrocyte numbers in the blood to maximize the uptake of oxygen from the thinner air.

8 0
2 years ago
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