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Firdavs [7]
2 years ago
10

Richardson Travel offers helicopter service from suburban towns to John F. Kennedy International Airport in New York City. Each

of its 15 helicopters makes between 1,000 and 2,000 ​round-trips per year. The records indicate that a helicopter that has made 1,000 ​round-trips in the year incurs an average operating cost of ​$350 per​ round-trip, and one that has made 2,000 ​round-trips in the year incurs an average operating cost of ​$300 per​ round-trip.
Using the​ high-low method, estimate the linear relationship y equals a plus bX​, where y is the total annual operating cost of a helicopter and X is the number of​ round-trips it makes to JFK airport during the year.
Business
1 answer:
Aloiza [94]2 years ago
5 0

Answer:

Y = $100,000 + $250X

Explanation:

For computing the linear relationship, first we need to compute the variable cost and fixed cost by using the high low method is shown below:

Before that first we have to determine the total cost

Total cost of 1,000 round-trips = $350 × 1,000 = $350,000

Total cost of 2,000 round-trips = $300 × 2,000 = $600,000

Now the variable cost per round trip is  

= ($600,000 - $350,000) ÷ (2,000 - 1,000)

= $250

Variable cost per round-trip is $300.

And, the fixed cost is

= $600,000 - 2,000 × $250

= $600,000 - $500,000

= $100,000

Now the linear relationship is

Y = $100,000 + $250X

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PRESENT VALUE OF AN ANNUITY Find the present values of these ordinary annuities. Discounting occurs once a year. 1. $600 per yea
NikAS [45]

Answer:

    ordinary   // annnuity-due

1.- 4,521.65   //  4,883.38

2.- 1,572.64  //  1,635.54

4.- 3,000.00 //  3,000

Explanation:

C \times \frac{1-(1+r)^{-time} }{rate} = PV\\

C 600.00

time 12

rate 0.08

600 \times \frac{1-(1+0.08)^{-12} }{0.08} = PV\\

PV $4,521.6468

Annuity-due

600 \times \frac{1-(1+0.08)^{-12} }{0.08}(1+0.08) = PV\\

PV $4,883.3786

C \times \frac{1-(1+r)^{-time} }{rate} = PV\\

C 300.00

time 6

rate 0.04

300 \times \frac{1-(1+0.04)^{-6} }{0.04} = PV\\

PV $1,572.6411

Annuity-due

1,572.6411 x 1.04 = $1,635.5467

4.- as interest rate is 0% the money do not lose value over time

will be 3,000 regardless of time or type of annuity

4 0
2 years ago
What identifies data outside of a normal condition?
skelet666 [1.2K]
<span>An Exception Report identifies data outside of normal conditions. </span>
7 0
2 years ago
Patrick Corporation inadvertently produced 10,000 defective personal radios. The radios cost $8 each to produce. A salvage compa
Anuta_ua [19.1K]

Answer

The answer and procedures of the exercise are attached in the following archives.

Step-by-step explanation:

You will find the procedures, formulas or necessary explanations in the archive attached below. If you have any question ask and I will aclare your doubts kindly.  

3 0
2 years ago
Work cell at Chris Ellis Commercial Laundry has a workstation with two​ machines, and each unit produced at the station needs to
choli [55]

Answer:

24 minutes

Explanation:

The computation of the process time of the work cell is shown below:

Throughput time is the time that is needed to produced a finished good product. It involves the manufacturing process time and the time for converting the raw material into a finished product

Therefore

Throughput time = [1 unit × (60 min ÷ 5 units)] × 2

                           = 24 minutes

6 0
2 years ago
The village of Hempstead has been taking a look at the issue of responding to 911 calls. It is a small community and geographica
yuradex [85]

Answer:

\bar X = \frac{17+12+9+16+14}{5}= 13.6min

So then the best answer for this case would be:

a. 13.6 minutes

Explanation:

For this case we have the following data for the response rates:

17,12,9,16,14

And we want to calculate the mean response time for 911 calls in this village.

And for this case we use we can use the definition of sample mean given by:

\bar X = \frac{\sum_{i=1}^n X_i}{n}

Where n = 5 represent the sample size for this case. If we replace we got:

\bar X = \frac{17+12+9+16+14}{5}= 13.6min

So then the best answer for this case would be:

a. 13.6 minutes

The sample mean is an estimator unbiased of the population mean because:

E(\bar X) = E(\frac{\sum_{i=1}^n X_i}{n}) = \frac{1}{n} \sum_{i=1}^n E(X_i) = \frac{n\mu}{n}= \mu

For this reason is a good statistic if we want to see central tendency in a group of values.

8 0
2 years ago
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