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Papessa [141]
2 years ago
13

Caroline, Colin & Sarah share some money.

Mathematics
1 answer:
julia-pushkina [17]2 years ago
4 0

Answer:

2/9

Step-by-step explanation:

After Caroline's share,

1 - 1/9 = 8/9 is left

Sarah gets:

1/(1+3) of 8/9

1/4 × 8/9

2/9

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a 12 foot tall building casts on 8 foot long long shadow. how long of a shadow will a 5 foot tall women have
grin007 [14]
This is just a basic proportion. 5/8 = x/12. So the 5 foot tall women would have a 7.5 foot shadow.
7 0
2 years ago
Sheila was given $20.00 for her birthday and spent $14.79 on a CD. How much was her change?
alexira [117]

Answer:

$5.21

Step-by-step explanation:

20.00 - 14.79 = 5.21

3 0
2 years ago
Read 2 more answers
Simplify x + 2/ x^2 - 6x - 16 divided by 1/9x
djverab [1.8K]
Hello there!

Simplify the expression
9/x(x - 8)

Hope this helps! :)
~Zain
7 0
2 years ago
Rita makes and sells necklaces. The materials to make each necklace cost $2.75. Last week she made 8 necklaces and wants to make
Tresset [83]

Answer:

The error she made was that she was adding x and 2.75. She should subtract 2.75 from x.

Another mistake that she made was that she sold each for $7 assuming that she would make a profit of 78, but she should see each necklace for $12.5 so that she could make a profit of $78.

Step-by-step explanation:

The error she made was that she was adding x and 2.75.

She should write the equation as 8 (x - 2.75) = 78; as she spends $2.75 to make a necklace.

By using the correct equation: 8 (x - 2.75) = 78

=> 8x - 22 = 78

=> 8x = 78 + 22

=> 8x = 100

=> x = 100/8

=> x = 12.5

Another mistake that she made was that she sold each for $7 assuming that she would make a profit of 78, but she should see each necklace for $12.5 so that she could make a profit of $78.

Hope this helps you.

3 0
2 years ago
Suppose a1=12−12,a2=23−13,a3=34−14,a4=45−15,a5=56−16. a) Find an explicit formula for an: . b) Determine whether the sequence is
lorasvet [3.4K]

I'm going to assume you meant to write fractions (because if a_n are all non-negative integers, the series would clearly diverge), so that

a_1=\dfrac12-\dfrac12

a_2=\dfrac23-\dfrac13

a_3=\dfrac34-\dfrac14

and so on.

a. If the pattern continues as above, we would have the general term

a_n=\dfrac n{n+1}-\dfrac1{n+1}=\dfrac{n-1}{n+1}

b. Note that we can write a_n as

a_n=\dfrac{n-1}{n+1}=\dfrac{n+1-2}{n+1}=1-\dfrac2{n+1}

The series diverges by comparison to the divergent series

\displaystyle\sum_{n=1}^\infty\frac1n

4 0
2 years ago
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