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2 years ago

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Mary Lou buys a package of 500 heels to decorate 4 different pairs of jeans. She uses the same number of jewels on each pair of

jeans. How many jewels will she uses for each pair of jeans?

1 answer:

jeka57 [31]2 years ago

4 0

You just want to do 500/4=125 jewels on each pair of jeans

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Roger is building a storage shed with wood blocks that are in the shape of cubic prisms. Can he build a shed that is twice as hi

Fynjy0 [20]

Given that Roger is building a storage shed with wood blocks that are in the shape of cubic prisms.

cube is basicallye a box which is made of squares. That is all the sides (lenght, width and height) are equal.

Now we have to determine, Can he build a shed that is twice as high as it is wide.

that means if width is 1 then height should be twice which is 2.

yes that is possible if we put one cubical prism over another cubical prism. then height of shed due to two prism will be twice than the width.

Hence correct choice should be "A. Yes. For every block of width, he could build two blocks high."

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2 years ago

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A jar contains black marbles and green marbles. Sixty percent of the marbles in the jar are green. A number generator simulates

grigory [225]

Answer: D

Step-by-step explanation:

The number generator is not fair, in most of the experiments, considerably less than 60 % of the selected marbles are green.

And if Sixty percent of the marbles in the jar are green. A number generator should simulates randomly by selecting atleast one of the 60% of green marbles from the jar

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If 30% is lost by selling a sofa set for RS 980, at what price must it be sold to gain 10%.

PSYCHO15rus [73]

Answer:

1078

Step-by-step explanation:

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second: take that value (98) and add it to 980

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A rate that describes how much smaller or larger the scale drawing is than the real object

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It is called a scale factor :)

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2 years ago

A producer of steel cables wants to know whether the steel cables it produces have an average breaking strength of 5000 pounds.

Sever21 [200]

Answer:

Step-by-step explanation:

Hello!

The producer needs his cables to have an average breaking strength of 5000 pounds. A lower average breaking strength means that the cable is not adequate, a higher average breaking strength results in an unnecessary increase in production costs.

The sample is of 64 steel cables and the breaking strength of the pieces was recorded.

I always recommend that the first step to any statistic exercise is to establish the study variable that way you'll have fresh in mind the kind of data set you are working with and the type of distribution to expect from them (for example if it is a discrete variable you'd expect a binomial distribution, a continuous variable leads to a normal distribution (exact or approximate) a categorical variable sets the path to work with non-parametrical statistics such as Chi-Square statistics.)

In this example the study variable is:

X: Breaking strength of a steel cable.

This variable is continuous so first I'll use the sample information to test its distribution. Keep in mind that one of the conditions to use the Student t-test is that the variable has a normal distribution.

The p-value for the normality test is 0.8512, comparing it with the level of significance of the test (α: 0.05) the decision is to not reject the null hypothesis of the normality test, so you can conclude that the breaking strength of the steel cables has a normal distribution:

X~N(μ;σ²)

1.

The standard error of the test is the square root of the variance.

Using the following formula you have to calculate the variance:

$S^2= \frac{1}{n-1}*(sumX^2-(\frac{(sumX)^2}{n} ))$

n=64

∑X= 330174.88

∑X²= 1718980202.34

$S^2= \frac{1}{63}*(1718980202.34-(\frac{(330174.88)^2}{64} ))$

S²= 2478376895

S= 497.8329 ≅497.833

2.

For this test the hypotheses are:

H₀: μ = 5000

H₁: μ ≠ 5000

$t= \frac{Xbar-Mu}{\frac{S}{\sqrt{n} } }$

The sample mean is:

Xbar= ∑X/n)= 330174.88/64=5158.98

‬ $t= \frac{5158.98-5000}{\frac{497.833}{\sqrt{64} } }$

t= 158.98/62.229= 2.555

3.

This test is two-tailed and so is the p-value. I've used statistics software to calculate it:

p-value 0.0131

4.

Using a significance level of 5%, since the p-value is less than α, the decision is to reject the null hypothesis. You can conclude at this level that the average breaking strength of the steel cables is different than 5000.

I hope this helps!

6 0

2 years ago