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vlada-n [284]
2 years ago
8

A tank holds 17 3/5 gallons after losing 36 2/3 gallons, 4 5/6 gallons,and 27 1/12 gallons in 3

Mathematics
2 answers:
elena55 [62]2 years ago
8 0

Answer:

Step-by-step explanation:

Given that A tank holds 17 3/5 gallons after losing 36 2/3 gallons, 4 5/6 gallons,and 27 1/12 gallons in 3

Consecutive days. If at the beginning the tank was 20 3/4 gallons short of capacity.

Tank full capacity = loss for 3 days + holding of tank after losing + shortage of capacity

To add these first let us convert these into improper fractions, then take lcd to add

Full capacity = \frac{88}{5} +\frac{110}{3} +\frac{29}{6} +\frac{325}{12} \\=\frac{88}{5} +\frac{440+58+325}{12} \\=\frac{1056+4115}{60} ==86.183 gallons

Rina8888 [55]2 years ago
4 0

Answer:Maybe if you studded you would have the answer young man

Step-by-step explanation:

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