I've included my code in the picture below. Best of luck.
Answer:
def sum_cubes(n):
if n == 1:
return 1
else:
return n * n * n + sum_cubes(n-1)
print(sum_cubes(3))
Explanation:
Create a function called sum_cubes that takes one parameter, n
If n is equal to 1, return 1. Otherwise, calculate the cube of n, and add it to the sum_cubes function with parameter n-1
If we want to calculate the cubes of the first 3 numbers:
sum_cubes(3) = 3*3*3 + sum_cubes(2)
sum_cubes(2) = 2*2*2 + sum_cubes(1)
sum_cubes(1) = 1
If you substitute the values from the bottom, you get 27+8+1 = 36
Answer:
C
Explanation:
myCar::accelerate()
here :: operator is used to access the member function outside the class.
we are calling accelerate() function using class and ::
21
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