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zhenek [66]
2 years ago
8

Si al numerador de una fraccion se añade 5, el valor de la fraccion es 2, y si al numerador se resta 2, al valor de la fraccion

es 1.Hallar la fraccion.
Mathematics
1 answer:
konstantin123 [22]2 years ago
6 0

Answer:

Respuesta.- La fracción es 9/7

Step-by-step explanation:

1) Llamando X e Y a la fracción, tenemos: X/Y

Si al numerador se le añade 5, es decir X+5, el valor de la fracción es 2, luego:

(X+5)/Y = 2

Y si al numerador se le resta 2, es decir X-2, el valor de la fracción es 1, luego:

(X-2)/Y = 1

Juntando amabas ecuaciones:

(X+5)/Y= 2

(X-2)/Y = 1

Despejando Y en ambas:

Y = (X+5)/2

Y = (X-2)..........(1)

Igualandolas:

(X+5)/2= (X-2)

De donde:

X+5 = 2X-4

X = 9

Y finalmente, sustituyendo el valor de X = 9 en la ecuaión (1), tendremos:

Y = (X-2)

Y = (9-2)

Y = 7

Respuesta.- La fracción es 9/7

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Compute i^1+i^2+i^3....i^99+i^100
fgiga [73]

Good morning ☕️

Answer:

<h3>i¹ + i² + i³ +. . .+ i⁹⁹ + i¹⁰⁰ = 0</h3>

Step-by-step explanation:

Consider the sum S = i¹ + i² + i³ +. . .+ i⁹⁹ + i¹⁰⁰

S =  i¹ +  i² +  i³ + . . . + i⁹⁹  +  i¹⁰⁰

S = a₁ + a₂ + a₃ +. . . + a₉₉ + a₁₀₀

then, S is the sum of 100 consecutive terms of a geometric sequence (an)

where the first term a1 = i¹ = i  and the common ratio = i

FORMULA:______________________

S=(term1)*\frac{1-(common.ratio)^{number.of.terms}}{1-(common.ratio)}

_______________________________

then

S=i*\frac{1-i^{100} }{1-i}

or i¹⁰⁰ = (i⁴)²⁵ = 1²⁵ = 1  (we know that i⁴ = 1)

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S = 0

7 0
2 years ago
A linear function that represents the number of hot dogs purchased at a football game is compared to a different linear function
Vsevolod [243]

Answer:

Key features: the functions can not be parallels, this means that their respective slopes can not be equal or multiple to the other

Step-by-step explanation:

Take for instance 2 linear functions,  and

If they intersect in some point in the space, say that is

Then (x1,y1)=(x3,y3), (x2.y2)= (x3,y3)

So, we can compare the two functions and get the following result;

It tells us that if M=m, we get an error, meaning that the functions are in fact parallels and there is no way that they meet in some point.

hope this helps!

5 0
2 years ago
Use the drop-down menus to complete the proof. Given that w ∥ x and y is a transversal, we know that ∠1 ≅∠5 by the . Therefore,
ololo11 [35]

Answer:

From the graph attached, we know that \angle 1 \cong \angle 5 by the corresponding angle theorem, this theorem is about all angles that derive form the intersection of one transversal line with a pair of parallels. Specifically, corresponding angles are those which are placed at the same side of the transversal, one interior to parallels, one exterior to parallels, like \angle 1 and \angle 5.

We also know that, by definition of linear pair postulate, \angle 3 and \angle 1 are linear pair. Linear pair postulate is a math concept that defines two angles that are adjacent and for a straight angle, which is equal to 180°.

They are supplementary by the definition of supplementary angles. This definition states that angles which sum 180° are supplementary, and we found that \angle 3 and \angle 1 together are 180°, because they are on a straight angle. That is, m \angle 3 + m \angle 1 = 180\°

If we substitute \angle 5 for \angle 1, we have m \angle 3 + m \angle 5 = 180\°, which means that \angle 3 and \angle 5 are also supplementary by definition.

4 0
2 years ago
Read 2 more answers
1. Walking to improve health. In a study investigating a link between walking and improved health (Social Science &amp; Medicine
lora16 [44]

Answer:

a) We need to conduct a hypothesis in order to check if the true average number of days in the past month that adults walked for the purpose of health or recreation is lower than 5.5 days (a;ternative hypothesis) , the system of hypothesis would be:  

Null hypothesis:\mu \geq 5.5  

Alternative hypothesis:\mu < 5.5  

b) For this case since we want to determine if the true mean is lower than an specified value is a one tailed test

c) For this case the significance level is given \alpha=0.01 and we want to find the critical value, so we need to find a critical value on the normal standard distribution who accumulate 0.01 of the area on the right tail and if we use excel or a table we got:

z_{cric}= -2.326

And the rejection zone would be: (\infty ,-2.326)

And the region is on the figure attached

Step-by-step explanation:

Part a: State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the true average number of days in the past month that adults walked for the purpose of health or recreation is lower than 5.5 days (a;ternative hypothesis) , the system of hypothesis would be:  

Null hypothesis:\mu \geq 5.5  

Alternative hypothesis:\mu < 5.5  

Part b

For this case since we want to determine if the true mean is lower than an specified value is a one tailed test

Part c

For this case the significance level is given \alpha=0.01and we want to find the critical value, so we need to find a critical value on the normal standard distribution who accumulate 0.01 of the area on the right tail and if we use excel or a table we got:

z_{cric}= -2.326

And the rejection zone would be: (\infty ,-2.326)

And the region is on the figure attached

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2 years ago
joyce is helping her aunt create craft kits. her aunt has 138 pipe cleaners, and each kit will include 6 pipe cleaners. what is
Andre45 [30]
23 pipe cleaners cause 23 x 6= 138
5 0
2 years ago
Read 2 more answers
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