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luda_lava [24]
2 years ago
3

David and Luisa are trying to determine if two samples are the same or different substances. First, they observed sample 1 and s

ample 2. Then, they wrote down their observations. Review their observations. Then, answer the questions below.
Which student’s observations would prove more useful to a chemist?

David's observations

Luisa's observations
Explain your answer below.

Biology
1 answer:
Igoryamba2 years ago
5 0

Answer:

Luisa's Observation.

Explanation:

Luisa's observation is explained better than David's was, and judging by the observations, David studied the same material, while Luisa's observation contained different description, meaning that there was likely more than one substance being observed and studied.

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The flowchart below shows the three generations of a cross between a pea plant that has yellow pods and a pea plant that has gre
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Hello. This question is incomplete. Also, you forgot to show the flowchart. The flowchart is attached below and the full question is:

The flowchart below shows the three generations of a cross between a pea plant that has yellow pods and a pea plant that has green pods. Green pods are the dominant trait. The flowchart is missing the labels that describe the traits.

In which squares should the phrase “Green pods” appear?

1.A and D  2.B and E  3.A,C and D  4.A,B,C,D and E

Answer:

3.A,C and D

Explanation:

As shown in the question above, the flowchart shows the crossing of a pea plant with dominant features (green pods - AA) and a pea plant with recessive features (yellow features - aa). The crossing between plants with AA and aa alleles generates a completely Aa population, which in this case, has the dominant characteristic, that is, it has green pods. This is because the "Aa" alleles are called heterozygous and develop the dominant characteristic.

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4 0
2 years ago
What combinations of alleles could result from a crossover between BD and bd chromosomes?
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Answer:

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The cross between two parents with genotype "BD" and "bd" will result into the following offspring -

B D

b Bb Db

d Bd Dd

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