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Helen [10]
2 years ago
11

A solid cylindrical metal is melted and recast into cubes of metal of sides 3cm . The base radius of the initial cylindrical met

al is 10.5cm and height is 63cm. How many cubes will be made
Mathematics
1 answer:
belka [17]2 years ago
8 0

Answer:

808

Step-by-step explanation:

The volume of the initial cylindrical metal must be equal to the total volume of the cubes.

Let the number of cubes made be x. Therefore:

V_C = V_c * x

where V_C = volume of the cylinder

V_c = volume of each cube

Each of the cubes have sides of length 3 cm.

The volume of a cube is given as:

V_c = L^3

where L = length of side of cube

Therefore, the volume of each cube is:

V_c = 3^3 = 27 cm^3

The volume of a cylinder is given as:

V_C = \pi r^2h

where r = radius

h = height of the cylinder

The volume of the cylinder is:

V_C = \pi * 10.5^2 * 63 = 21823.55 cm^3

Therefore:

21823.55 = 27 * x

=> x = 21823.55 / 27

x = 808.27

Since the number of cubes can only be a whole number, the number of cubes that will be made is 808.

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ivanzaharov [21]
Total hours working = 4.5 hrs 
hours doing laundry = 1 hr 

Percentage of time doing laundry = 1/4.5 
Percentage of time doing laundry = 22.22%

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4. Samantha is studying the geometric design of roads. She uses a surveying tool to measure the angles
algol13

Answer: the value of x is 8, the measure of angle A is 42, angles A and B are same side interior angles.

Step-by-step explanation:

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1 year ago
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Pherris is graphing the function f(x) = 2(3). He begins with the point (1,6). Which could be the next point on his graph?
djverab [1.8K]

Answer:

Its actually (2,18)

3 0
1 year ago
A production line operates with a mean filling weight of 16 ounces per container. Overfilling or underfilling presents a serious
Dominik [7]

Answer:

Part1) z=\frac{16.32-16}{\frac{0.8}{\sqrt{30}}}=2.191    

p_v =2*P(Z>2.191)=0.0284

Readjustment is needed

Part 2)  z=\frac{15.82-16}{\frac{0.8}{\sqrt{30}}}=-1.232    

z=\frac{15.82-16}{\frac{0.8}{\sqrt{30}}}=-1.232    

p_v =2*P(Z

No readjustment is needed

Step-by-step explanation:

Data given and notation

Part 1    

\bar X=16.32 represent the sample mean    

\sigma=0.8 represent the population standard deviation    

n=30 sample size    

\mu_o =16 represent the value that we want to test    

\alpha=0.05 represent the significance level for the hypothesis test.    

z would represent the statistic (variable of interest)    

p_v represent the p value for the test (variable of interest)    

State the null and alternative hypotheses.    

We need to apply a two tailed test.    

What are H0 and Ha for this study?    

Null hypothesis:  \mu =16    

Alternative hypothesis :\mu \neq 16    

Compute the test statistic  

The statistic for this case is given by:    

z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}} (1)    

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".    

Calculate the statistic    

We can replace in formula (1) the info given like this:    

z=\frac{16.32-16}{\frac{0.8}{\sqrt{30}}}=2.191    

Give the appropriate conclusion for the test  

Since is a two tailed test the p value would be:    

p_v =2*P(Z>2.191)=0.0284

Using the value of \alpha =0.05 we see that pv and we have enough evidence to reject the null hypothesis.

Readjustment is needed

The rejection zone is given by:

(-\infty ;-1.96) , (1.96;\infty)    

Part 2

\bar X=15.82 represent the sample mean    

We can replace in formula (1) the info given like this:    

z=\frac{15.82-16}{\frac{0.8}{\sqrt{30}}}=-1.232    

Give the appropriate conclusion for the test  

Since is a two tailed test the p value would be:    

p_v =2*P(Z

Using the value of \alpha =0.05 we see that pv>\alpha and we have enough evidence to FAIL to reject the null hypothesis.

No readjustment is needed

The rejection zone is given by:

(-\infty ;-1.96) , (1.96;\infty)  

What action would you recommend ?

Review the procedure.

Do you reach the same conclusion ?

No we got different conclusions

5 0
2 years ago
The box office took in a total of $2905 in paid admissions for the high-school musical. Adult tickets cost $8 each, and student
Svet_ta [14]
There are no equations to choose from but it should look like the following.

a= # of adult tickets
s= # of student tickets

QUANTITY EQUATION
a + s= 560

COST EQUATION
$8a + $3s= $2905

***If you have to also solve for the number of adults and students, here are the steps.

STEP 1:
multiply quantity equation by -8

-8(a + s)= -8(560)
-8a - 8s= -4480

STEP 2:
add cost equation and step 1 equation

$8a + $3s= $2905
-8a - 8s= -4480
a term cancels out to zero
-5s= -1575
divide both sides by -5
s= 315 students

STEP 3:
substitute s=315 in quantity equation
a + s= 560
a + 315= 560
subtract 315 from both sides
a= 245 adults

ANSWER:
Quantity Equation
a + s= 560

Cost Equation
$8a + $3s= $2905

Hope this helps! :)
7 0
2 years ago
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